Question

C Determine the coulomb's force between the electron and the nucleus in

Answer 1

Answer:

F = 2.3 x 10⁻⁸  N

Explanation:

Given,

The mean distance between the electron and the nucleus, x = 1 x 10⁻¹⁰ m

The number of protons present in the nucleus of the hydrogen atom is 1.

The charge of the proton and electron,  q = 1.602 x 10⁻¹⁹ C

Since they have opposite charges, the force between them is attractive,

The coulomb law of force between two charges is given by the formula,

                          $F=\frac{1}{4\pi\epsilon_{0}}\frac{qq}{x^{2}}$

                           $\frac{1}{4\pi\epsilon_{0}}$   = 9 x 10⁹ Nm²C⁻²

Substituting the values in the above equation

                              F = 9 x 10⁹ X (1.602 x 10⁻¹⁹)² / (1 x 10⁻¹⁰)²

                                 = 2.31 x 10⁻⁸  N

Hence, the force between the nucleus and electron of hydrogen atom is, F = 2.3 x 10⁻⁸  N