Initial velocity, u = 40 m/s
Final velocity, v = ?
t = 2s
g ≈ 9.8 m/s²
v = u + gt. Since it is a free fall, acceleration due to gravity, g
v = 40 + 9.8*2
<span>v = 59.6 m/s</span>
Answer:
(a) W=217 J
(b) Tc=378K
(c) e=0.39=39%
Explanation:
For part (a)
We to calculate the mechanical work W the engine does. By knowing QC and QH can obtain the work using equation
W = IQHI — IQcl .....................eq(1)
Put given values for QH and QC into equation (1) to get
the mechanical work of the engine
W = 550 - 335
W=217 J
For part (b)
We want to determine the temperature of low temperature reservoir which means Tc
IQc|/|Qh| =TC/TH
for Tc
Tc=(IQc|/|Qh|)*TH
Now we can put values
Tc= 620K (335/
550.1)
Tc=378K
For part (c)
Here we want to find the thermal efficiency (e) of the cycle
e=1-TC/TH
e=1-(378/620)
e=0.39=39%
Answer:
The maximum speed of the heart wall during the motion is 0.032 m/s
Explanation:
Given:
A = amplitude of vibration = 1.7 mm = 1.7x10⁻³m
f = frequency = 3 Hz
The angular velocity is:
The maximum speed of the heart wall during the motion is equal to:
Answer: 6.12metres
Explanation:
The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ
Recall that Wavespeed (V) = Frequency F x wavelength λ
V = F λ
In this case,
Wavespeed of sound = 1530 m/s
Frequency of sound = 2.50 x 10^2 Hz
Wavelength = ? (let the unknown value be Z)
Apply V = F λ
1530 m/s = 2.50 x 10^2 Hz x Z
Z = (1530 m/s / 2.50 x 10^2 Hz)
Z = (1530 m/s / 250Hz)
Z = 6.12m
Thus, the wavelength of sound in sea water is 6.12m
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