Answer:
It would change the amount of heat produced in the transmission line to four times the previous value.
Explanation:
Given;
initial voltage in the transmission line, V₁ = 500 kV = 500,000 V
Final voltage in the transmission line, V₂ = 1 MV = 1,000,000
The power lost in the transmission line due to heat is given by;

Power lost in the first wire;


Power lost in the second wire

Keeping the resistance constant, we will have the following equation;


Therefore, it would change the amount of heat produced in the transmission line to four times the previous value.