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klemol [59]
3 years ago
9

If a power utility were able to replace an existing 500 kV transmission line with one operating at 1 MV, it would change the amo

unt of heat produced in the transmission line to
Physics
1 answer:
mestny [16]3 years ago
8 0

Answer:

It would change the amount of heat produced in the transmission line to four times the previous value.

Explanation:

Given;

initial voltage in the transmission line, V₁ = 500 kV = 500,000 V

Final voltage in the transmission line, V₂ = 1 MV = 1,000,000

The power lost in the transmission line due to heat is given by;

P = \frac{V^2}{R}

Power lost in the first wire;

P_1 = \frac{V_1^2}{R}

R = \frac{V_1^2}{P_1}

Power lost in the second wire

P_2 = \frac{V_2^2}{R}\\\\ R = \frac{V_2^2}{P_2}

Keeping the resistance constant, we will have the following equation;

\frac{V_2^2}{P_2} = \frac{V_1^2}{P_1} \\\\P_2 = \frac{V_2^2P_1}{V_1^2}\\\\

P_2 = \frac{(1,000,000)^2P_1}{(500,000)^2}\\\\P_2 =4P_1

Therefore, it would change the amount of heat produced in the transmission line to four times the previous value.

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after stating a hypothesis, what is thew next step that a physicist is most likwely to take in answering a question
kifflom [539]

Answer:

Planning and performing an experiment to answer the question.

Explanation:

5 0
3 years ago
A radioactive substance decays exponentially. A scientist begins with 200 milligrams of a radioactive substance. After 17 hours,
lianna [129]

75.17 mg of the radioactive substance will remain after 24 hours.

Answer:

Explanation:

Any radioactive substance will obey the exponential decay behavior. So according to this behavior, any radioactive substance will be decaying in terms of exponential form of disintegration constant and Time.

Disintegration constant is the rate of decay of radioactive elements. It can be measured using the half life time of the radioactive element .While half life time is the time taken by any radioactive element to decay half of its concentration. Like in this case, at first the scientist took 200 mg then after 17 hours, it got reduced to 100 g. So the half life time of this element is 17 hours.

Then Disintegration constant = 0.6932/Half Life time

Disintegration constant = 0.6932/17=0.041

Then as per the law of disintegration constant:

N = N_{0}e^{-xt}

Here N is the amount of radioactive element remaining at time t and N_{0} is the initial amount of sample, x is the disintegration constant.

So here, N_{0} = 200 mg, x = 0.041 and t = 24 hrs.

N = 200 ×e^{-24*0.041} =75.17 mg.

So 75.17 mg of the radioactive substance will remain after 24 hours.

3 0
3 years ago
A meteorite strikes the Moon at the speed of 11 km/s. It has KE of 60,500,000 J. What will be its mass?
Vikentia [17]
KE=1/2 mv²
60,500,000 = 1/2 m ( 11,000 m/s )²
60,500,000= 1/2 ( 11,000 )² m
60,500,000= 60,500,000 x m
m= 60,500,000/60,500,000
m= 1 kg
8 0
3 years ago
A 30 kg girl and a 25 kg boy face each other on friction-free roller skates. The girl pushes the boy, who moves away at a speed
Dovator [93]

Answer: 4m/s

Explanation:

Mass of girl = m1 = 30kg

Mass of boy = m2 = 25kg

Resultant speed after collision = 1.0m/s

Speed of girl = v1

Speed of boy = v2

Momentum = mass × velocity

m1v1 - m2v2 = mv

30v1 - 25v2 = 1×m

30v1 - 25v2 = m

v1 = (m + 25v2)/30 ...eqn 1

but m1 - m2 = m

m = 30 - 25 = 5kg

v1 = (5 + 25v2)/30 ...eqn 2

v1-v2 = 1m/s

v2 = (v1 - 1)m/s

Substitute for v2 in eqn 2

v1 = [5 + 25(v1 - 1)]/30

30v1 = 5 + 25v1 - 25

30v1 - 25v1 = -20

5v1 = -20

v1 = -4m/s

Because she moved in an opposite direction to the boy, the negative sign is featured on her speed

3 0
3 years ago
Branches of sicence​
Sonja [21]

Answer:

physical science

earth science and life science

5 0
3 years ago
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