Answer:
Distance covered is equal to all the distance traveled.
So for example, if you go from A to B, and then from B to C, the total distance covered is AB + BC.
Displacement is equal to the difference between the final position and the initial position.
So if we go from A to B, the displacement is simply the line AB.
While if we go from A to B, and then from B to C, the displacement will be a segment that directly connects A and C, such that:
displacement = √( (AB)^2 + (BC)^2)
Now, if we want to find the points such that the magnitude of the distance covered is equal to the magnitude of the displacement, we need to look at the pairs that are directly connected by a straight line.
Those are:
A to B ( or B to A)
B to C (or C to B)
C to D (or D to C)
For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as
du=0.2512J
<h3>What is the largest potential energy difference (in Joules) you can find between two orientations?</h3>
Generally, the equation for the initial velocity is mathematically given as
v0=-iAB
Therefore
-2*\pi(0.2)(0.5))
v0=-0.1256J
for 180
theta=0180=-iABcos180
V180=0.1256J
Therefore
du=v180-v0
0.1258-(-0.1256
du=0.2512J
In conclusion, potential energy
du=0.2512J
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Answer:
Explanation:
It is given that,
Length of the wire, L = 0.6 m
Current flowing inside the wire, I = 2 A
Uniform magnetic field, B = 0.3 T
Force experienced by the wire in the magnetic field, F = 0.18 N
To find,
The angle made by the wire with the magnetic field.
Solve,
We know that the magnetic force acting on the wire inside the magnetic field is given by :
Therefore, the wire makes an angle of 30 degrees with respect to magnetic field.