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Daniel [21]
3 years ago
10

The anticodon is the three-base code on the tRNA molecule that binds to the codon on mRNA. What is the associated codon for the

anticodon UUA?
Chemistry
2 answers:
neonofarm [45]3 years ago
5 0
It is AAU
A-U
U-A
C-G
G-C
denis-greek [22]3 years ago
5 0
The associated codon is AAU
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The heat of vaporization of 1–pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K•mol. What is the approximate b
tensa zangetsu [6.8K]

Answer:

375 K

Explanation:

Using the experssion shown below as:

\Delta G^0=\Delta H^0_{vap}-T\Delta S^0_{vap}

At vaporization point, the liquid and the gaseous phase is in the equilibrium.

Thus,

\Delta G^0=0

So,

Delta H^0_{vap}=T\Delta S^0_{vap}

Given that:

Delta H^0_{vap}=55.5\ kJ/mol

Also, 1 kJ = 10³ J

So,

Delta H^0_{vap}=55500\ J/mol

\Delta S^0_{vap}=148\ J/K.mol

So, temperature is :

T=\frac{Delta H^0_{vap}}{\Delta S^0_{vap}}

T=\frac{55500}{148}

<u>T= 375 K</u>

3 0
3 years ago
How many liters of plasma are present in 8.5 pints?
stellarik [79]

Answer:

there are 4.0205 Litres of plasma in 8.5 pints

Explanation:

Recall that:

1 quart qt = 2 pints pt  and 1 quart = 946 mL

∴ two pints will contain 946 mL

and one pint will be = 946 mL/2

=  473 mL

Similarly, 8.5 pints will contain 473 mL × 8.5 = 4020.5  mL

We know that :

1000 mL = 1 Litres

Hence 4020.5 mL = (4020.5 /1000)L

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Therefore, there are 4.0205 Litres of plasma in 8.5 pints

4 0
3 years ago
Is baking cake a acid base reaction
Zinaida [17]
When baking powder is added to a cake, the acid base reaction it undergoes with the acidic butter produces the carbon dioxide that makes the cake rise.
6 0
3 years ago
If the mass of 23 gummi bears is 49.2g, what is the average mass of one gummi bear? Round answer to the nearest 0.00g (do NOT ty
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just divide the mass 49.2 grams by the amount of gummi bears 23 to get the answer of 2.1391 then it says to round to 2 decimals so 2.14 grams

3 0
3 years ago
SHOW WORK AND INCLUDE UNITS
Ber [7]

Answer:

36365.4 Joules

Explanation:

The quantity of Heat Energy (Q) released on cooling a heated substance depends on its Mass (M), specific heat capacity (C), and change in temperature (Φ)

Thus, Q = MCΦ

Since, M = 45.4 g

C = 3.56 J/g°C,

Φ = 250°C - 25°C = 225°C

Q = 45.4g x 3.56J/g°C x 225°C

Q= 36365.4 Joules

Thus, 36365.4 Joules of heat energy is released when the lithium is cooled.

6 0
3 years ago
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