Find A intersection B.

1 answer:

3 0

A: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}
B: {-2, -1, 1, 4, 7, 11}

A ∩ B = {1, 4, 7, 11}

So the answer is B.

Intersection of two or more sets cointains only common elements.

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LA and B are vertical angles. If m_A = (5x + 5) and m_B = (4x + 29), then find the measure of_A.

OverLord2011 [107]

Answer:

If A and B are vertical angles, then they are congruent, so their measures are equal.

This means

(5x + 5)º = (4x + 29)º

5x + 5 = 4x + 29

x = 24

Then angle A has measure (5*24 + 5)º = 125º.

Step-by-step explanation:

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Answer:

$\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]$

Step-by-step explanation:

To add matrices, we add the corresponding components.

The given matrices is

$\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]$

We add the corresponding components to get;

$\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}3+6&9+0\\5+-8&-2+4\end{array}\right]$

We simplify to get:

$\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]$

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Directed line segment has endpoints P(– 8, – 4) and Q(4, 12). Determine the point that partitions the directed line segment in a

larisa86 [58]

Answer:

Point (1,8)

Step-by-step explanation:

We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.

When a point divides any segment internally in the ratio m:n, the formula is:

$[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]$