One mole of C= 12 grams
two moles of O =32
so one mole of CO^2 is44 grams
.1 moles or 1/10 moles of 44 grams is 4.4 grams
Moles of CaBr2 = 5/molar mass of CaBr2
= 5/199.886
= 0.025 moles.
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Answer:
c
Explanation:
total production of the three shifts/ total of prediction of each yield x 100%
Answer:
P₂ = 647 torr
Explanation:
Given data:
Initial pressure = 565 torr
Initial temperature = 27°C
Final temperature = 71°C
Final pressure = ?
Solution:
Initial temperature = 27°C (27+273 = 300 K)
Final temperature = 71°C (71+273 = 344 K)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
565 torr / 300K = P₂/344 K
P₂ = 565 torr × 344 K / 300 K
P₂ = 194360 torr. K /293 K
P₂ = 647 torr
