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2 years ago

What is the filtrate?

Chemistry

1 answer:

kondaur [170]2 years ago

5 0

Answer:

a liquid which has passed through a filter.

Explanation:

Filtration is a physical separation process that separates solid matter and fluid from a mixture using a filter medium that has a complex structure through which only the fluid can pass

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Balance each chemical equation. Hg2(C2H3O2)2(aq)+KCl(aq)→Hg2Cl2(s)+KC2H3O2(aq)

Ira Lisetskai [31]

Answer:

Explanation:

When potassium chloride reacts with lead acetate in aqueous medium, it gives white precipitate of lead chloride and potassium acetate in aqueous medium as a product.

As shown in chemical reaction given below:

4 0

2 years ago

2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'

Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

$\displaystyle M_1V_1= M_2V_2$

Where M represents molarity and V represents volume.

Let the initial concentration and unknown volume be M₁ and V₁, respectively. Let the final concentration and required volume be M₂ and V₂, respectively. Solve for V₁:

$\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}$

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
$\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}$

Convert this value to mL:
$\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}$

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0

2 years ago

If a container holds 1mol of hydrogen, 2.5mol of helium, and 2mol of oxygen at a total pressure of 4atm, what is the partial pre

nlexa [21]

Answer:

Partial pressure O₂ = 1.78 atm

Explanation:

We can apply the mole fraction to solve the question:

Moles of gas / Total moles = Partial pressure of gas / Total pressure

Total moles = 1 H₂ + 2.5 He + 2O₂ = 4.5 moles

2 mol O₂ / 4.5 mol = Partial pressure O₂ / 4 atm

(2 mol O₂ / 4.5 mol ) . 4 atm = Partial pressure O₂ → 1.78 atm

7 0

3 years ago

Read 2 more answers

Given that a sample of air is made up of nitrogen, oxygen, and argon in the mole fraction 0.78 N2, 0.21 O2, and 0.010 Ar, what i

Artist 52 [7]

Answer:

1.293 kg/m³

Explanation:

Density: this can be defined as the ratio of the mass of a body and its volume.

The S.I unit of density is kg/m³

D = m/v............................ Equation 1

D = density of air, m = mass of air, v = volume of air.

Note: Since the air is made up of nitrogen, oxygen and argon. the mass and volume of air will be the sum of the mass and sum of the volume of nitrogen, oxygen, and argon respectively.

(i) Mass of one mole of N₂ = 28 g

Therefore, mass of 0.78 mole of N₂ = 28×0.78 = 21.84 g.

(ii) Mass of one mole of O₂ = 32 g

Therefore, mass of 0.21 mole of O₂ = 32×0.21 = 6.72 g

(iii) Mass of one mole of Ar = 40 g

Therefore mass of 0.01 mole of Ar = 0.01×40 = 0.4 g

m = 21.84 + 6.72 + 0.4 = 28.96 g

Also Note: One mole of every gas at standard temperature and pressure = 22.4 dm³

Therefore,

(i) volume of 0.78 mole of N₂ = 22.4×0.78 = 17.47 dm³

(ii) volume of 0.21 mole of O₂ = 0.21×22.4 = 4.704 dm³

(iii) volume of 0.01 mole of Ar = 0.01×22.4 = 0.224 dm³

Therefore,

v = 17.47+4.704+0.224

v = 22.398 dm³

Substituting the value of v and m into equation 1

D = 28.96/22.398

D = 1.293 g/dm³

D = 1.293 kg/m³

5 0

4 years ago

Read 2 more answers

1S Called A simple machine that has a disc with a grooved rim to wind up asing is called When a fixed pulley and a movable nugnk

maxonik [38]

what is the question??

3 0

3 years ago

Read 2 more answers