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Mashcka [7]
3 years ago
6

A tree casts a 25 foot shadow. At the same time of day, a 6 foot man standing near the tree casts a 9 foot shadow. What is the a

pproximate height of the tree to the nearest foot?
Mathematics
2 answers:
kirza4 [7]3 years ago
7 0
Ratio of height of the man to the length of the shadow = 6:9 = 2:3
Ratio of height of the tree to the length of its shadow = x:25 = 2:3
x/25 = 2/3
x = (25 x 2)/3 = 50/3 = 16.67

Therefore the approximate height of the tree to the nearest foot is 17 feet.
Bumek [7]3 years ago
4 0
The question ask to calculate and find the approximate height of the tree to the nearest foot if it has cast a shadow of 25feet and the man also cast a shadow near it at a height of 6 foot. So base on that fact, I came up with an answer of approximately 17 feet. I hope you are satisfied with my answer
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EXPLANATION

The given identity is

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Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

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We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

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