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3 years ago

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Help please! I need to write 4y =-3x + 12 in standard form, find the y-intercept of the previous equation, as an ordered pair, a

nd find the x-intercept of the previous equation, but I forgot how. I need the answer asap! Thank you!

1 answer:

damaskus [11]3 years ago

5 0

Answer:

$-3x+4y=12\\y-intercept: (0,3)\\x-intercept: (-4,0)$

Step-by-step explanation:

The standard form of a linear equation is $ax+by=c$ , where $a$ , $b$ , and $c$ are constants in the equation.

Based on the equation you have provided, the standard form would be $-3x+4y=12$ , where $a=-3, b=4, c=12$ .

To find the y-intercept, set $x=0$ .

$-3(0)+4y=12\\0+4y=12\\4y=12\\y=\frac{12}{4} =3$

Therefore, the y-intercept is $(0,3)$ .

Do the same thing for the x-intercept, but this time with $y=0$ .

$-3x+4(0)=12\\-3x+0=12\\-3x=12\\x=\frac{12}{-3} =-4$

Therefore, the x-intercept is $(-4,0)$ .

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Given:

$1. -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$$

To find:

The product of the polynomials.

Solution:

1. $-3 x^{2}\left(4 x^{3}-7\right)$ $=-3 x^{2}(4 x^{3}) -3 x^{2}(-7)$

Multiply the numerical coefficient and add the powers of x.

$=-12 x^{5}+21 x^{2}$

2. $(6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

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$=12 x^2+8x-15$

3. $(3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)$

Multiply each term of first polynomial with each term of 2nd polynomial.

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Add or subtract like terms together.

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Step-by-step explanation:

The slope is the x axis which goes first

and the y intercept would be the y axis which goes second

Slope goes before the y intercept

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Step-by-step explanation:

Discount:

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Round that to 58.15

* Turn 20% into a decimal (0.2)

Cost after Discount:

290.76 - 58.15 = 232.61

Sales Tax:

First turn 6.25 % into a decimal. Which would be 0.0625.

0.0625 × 232.61* = 14.556875

Then we round to the nearest hundredth and you get 14.56.

* We us the amount after the discount instead of the original price.

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