Question

Help please! I need to write 4y =-3x + 12 in standard form, find the y-intercept of the previous equation, as an ordered pair, and find the x-intercept of the previous equation, but I forgot how. I need the answer asap! Thank you!

Answer 1

Answer:

$-3x+4y=12\\y-intercept: (0,3)\\x-intercept: (-4,0)$

Step-by-step explanation:

The standard form of a linear equation is $ax+by=c$, where $a$ , $b$, and $c$ are constants in the equation.

Based on the equation you have provided, the standard form would be $-3x+4y=12$, where $a=-3, b=4, c=12$.

To find the y-intercept, set $x=0$.

$-3(0)+4y=12\\0+4y=12\\4y=12\\y=\frac{12}{4} =3$

Therefore, the y-intercept is $(0,3)$.

Do the same thing for the x-intercept, but this time with $y=0$.

$-3x+4(0)=12\\-3x+0=12\\-3x=12\\x=\frac{12}{-3} =-4$

Therefore, the x-intercept is $(-4,0)$.