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AveGali [126]
3 years ago
14

Select all the correct functions. Identify all the functions that have a greater rate of change than the function represented in

the graph. y = 2x + 7 y = 0.5x -5 y = 3x + 12 y = 1.5x - 1 y = 2.5x - 20 y = x + 7
Mathematics
1 answer:
RoseWind [281]3 years ago
5 0

Answer:

y=2x+7

Step-by-step explanation:

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2. Two of the radii for the inscribed circle below have the expression 2x -8 and 4x
expeople1 [14]

Answer:

13

Step-by-step explanation:

6 0
2 years ago
Im stuck on this one​
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What????????????????????????????
5 0
3 years ago
Pls answer ASAP
Alex Ar [27]

Answer:

first answer

Step-by-step explanation:

the first symbols mean : congruent.

the second symbols mean : parallel.

therefore answer option 1 is the direct translation of "if opposite sides of a quadrilateral are congruent, then it is a parallelogram" (= each of the 2 pairs of opposite sides consists of parallel sides).

4 0
2 years ago
Work out the length of the perimeter.
PilotLPTM [1.2K]
Try this option:
According to property such triangle
1. area=0.5*a*b, where a and b - the sides of angle 90°.
Using this equation: 180=0.5*40*b, ⇒ b=9.
2. c²=a²+b², ⇒c=√(9²+40²)=41 - the third side of the triangle;
3. Perimeter=a+b+c=9+40+41=90 cm.

answer: 90 cm.
3 0
3 years ago
Which of the following are square roots of —8 + 8i/3? Check all that apply.
8090 [49]

Answer:

Options (2) and (3)

Step-by-step explanation:

Let, \sqrt{-8+8i\sqrt{3}}=(a+bi)

(\sqrt{-8+8i\sqrt{3}})^2=(a+bi)^2

-8 + 8i√3 = a² + b²i² + 2abi

-8 + 8i√3 = a² - b² + 2abi

By comparing both the sides of the equation,

a² - b² = -8 -------(1)

2ab = 8√3

ab = 4√3 ----------(2)

a = \frac{4\sqrt{3}}{b}

By substituting the value of a in equation (1),

(\frac{4\sqrt{3}}{b})^2-b^2=-8

\frac{48}{b^2}-b^2=-8

48 - b⁴ = -8b²

b⁴ - 8b² - 48 = 0

b⁴ - 12b² + 4b² - 48 = 0

b²(b² - 12) + 4(b² - 12) = 0

(b² + 4)(b² - 12) = 0

b² + 4 = 0 ⇒ b = ±√-4

                     b = ± 2i

b² - 12 = 0 ⇒ b = ±2√3

Since, a = \frac{4\sqrt{3}}{b}

For b = ±2i,

a = \frac{4\sqrt{3}}{\pm2i}

  = \pm\frac{2i\sqrt{3}}{(-1)}

  = \mp 2i\sqrt{3}

But a is real therefore, a ≠ ±2i√3.

For b = ±2√3

a = \frac{4\sqrt{3}}{\pm 2\sqrt{3}}

a = ±2

Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)

Options (2) and (3) are the correct options.

6 0
3 years ago
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