I believe the answer is 3

Simplify
to 

Both are over 11, so, just sum.


Answer:
The coordinates are
and
.
Step-by-step explanation:
First, we have to derive an expression for translation under the assumption that each point of XYZ experiments the same translation. Vectorially speaking, translation from X to X' is defined by:
(1)
Where
is the vector translation.
If we know that
and
, then the vector translation is:



Then, we determine the coordinates for Y' and Z':






The coordinates are
and
.
Using the cosine double angle formula,

(Note I took the positive case since
terminates in the first quadrant)
Using the Pythagorean identity,

(Note I took the positive case since
terminates in the first quadrant)
Answer:
7
Step-by-step explanation:
18 - 4 = 14
14/2 = 7