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dem82 [27]
3 years ago
11

MATH QUESTION: Julie bought a bag of parsnips that weighed 4 2/7 pounds. She also bought a bag of turnips that weighed 1 1/3 tim

es as much as the parsnips. How many pounds of turnips did Julie buy? Express your answer as a simplified mixed number.
Mathematics
1 answer:
kati45 [8]3 years ago
5 0

Answer:

Julie buy 5\frac{5}{7} pounds of turnips.

Step-by-step explanation:

We are given that Julie bought a bag of parsnips that weighed (4\frac{2}{7}) pounds. She also bought a bag of turnips that weighed (1\frac{1}{3}) times as much as the parsnips.

We have to find how many pounds of turnips did Julie buy.

Firstly, the weight of a bag of parsnips that Julie bought = 4\frac{2}{7} = \frac{30}{7} pounds

Now, it is stated that she bought a bag of turnips that weighed (1\frac{1}{3}) times as much as the parsnips, that means;

Weight turnips bag = \frac{4}{3} \times \frac{30}{7}

                              = 4 \times \frac{10}{7}

                              = \frac{40}{7}

So, Julie buy 5\frac{5}{7} pounds of turnips.

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The equations -6x + 3y = 6 and x² + y = 10 intersect at the
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The values of the letters in coordinates (a, b) and (c,d) are;

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We are given two equations;

-6x + 3y = 6  ---(eq 1)

x² + y = 10 ---(eq 2)

  • We are told that they intersect at coordinates; (a, b) and (c, d).

Let us make y the subject in eq 2 to get;

y = 10 - x²  --(eq 3)

  • Let us put 10 - x² into eq 1 to get;

-6x + 3(10 - x²) = 6

expanding further gives;

-6x + 30 - 3x² = 6

rearranging gives;

3x² + 6x - 24 = 0

Using online quadratic equation <em>solver</em>, we have;

x = -4 and x = 2

Putting x = -4 into eq 3 gives;

y = 10 - (-4)²

y = 10 - 16

y = -6

Putting x = 2 into eq 3 gives;

y = 10 - (2)²

y = 10 - 4

y = 6

  • Thus, the coordinates are; (-4, -6) and (2, 6)

Comparing with (a, b) and (c,d), we have;

a = -4

b = -6

c = 2

d = 6

Read more at; brainly.com/question/15165519

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