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Anarel [89]
3 years ago
8

A car starts from rest and speeds up at 2.2m/s^2 after the traffic light turns green , how far will it have gone when it os trav

eling at 18m/s?
PLZ write down the steps and the equation you used and thx <3
Physics
1 answer:
alex41 [277]3 years ago
3 0

73.6m

Explanation:

Initial velocity, U = 0

moving velocity, V = 18m/s

 Acceleration = 2.2m/s²

Unknown:

Distance covered = ?

Solution:

 we have to use the appropriate equation of motion to solve this problem

           V² = U² +2as

    V is the final velocity

    U is the initial velocity

     a is the acceleration

     s is the distance

  since u = 0

             V² = 2as

             18²  = 2 x 2.2 x s

            324 = 4.4s

                  s = \frac{324}{4.4} = 73.6m

Learn more:

Motion brainly.com/question/2607086

#learnwithBrainly

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If an object is thrown in an upward direction from the top of a building 160 ft. High at an initial speed of 21.82 mi/h what is
viktelen [127]
To solve this problem we are going to use tow kinematic equations for falling objects.
1. Kinematic equation for final velocity: V_{f}=V_{i}+gt
where
V_{f} is the final velocity 
V_{i} is the initial velocity 
g is the acceleration due to gravity 32 \frac{ft}{s^2}
t is the time 
2. Kinematic equation for distance: d=V_{i}t+ \frac{1}{2} gt^2
where
d is the distance 
V_{i} is the initial velocity 
V_{f} is the final velocity
g is the acceleration due to gravity 32 \frac{ft}{s^2}
t is the time 

First, we are going to convert 21.82 mi/h to ft/s:
21.82 \frac{mi}{h} =31.21 \frac{ft}{s}

Next, we are going to use the first equation to find how long it takes for the rock to reach its maximum height.
We know for our problem that the object is thrown in upward direction, so its velocity at its maximum height (before falling again) will be zero; therefore: V_{f}=0. We also know that it initial speed is 31.21 ft/s, so V_{i}=31.21. Lets replace those values in our formula to find t:
V_{f}=V_{i}+gt
0=31.21+(-32)t
-32t=-31.21
t= \frac{-31.21}{-32}
t=0.98seconds

Next, we are going to use that time in our second kinematic equation to find the distance the object reach at its maximum height:
d=V_{i}t+ \frac{1}{2} gt^2
d=31.21(0.98)+ \frac{1}{2} (-32)(0.98)^2
d=15.22ft 

Now we can add the height of the building and the maximum height of the object:
d=160+15.22=175.22ft

Next, we are going to use that height (distance) in our second kinematic equation one more time to fin how long it takes for the object to fall from its maximum height to the ground:
d=V_{i}t+ \frac{1}{2} gt^2
175.22=31.21t+ \frac{1}{2} (32)t^2
16t^2+31.21t-175.22=0
t=2.47 or t=-4.43
Since time cannot be negative, t=2.47 is the time it takes the object to fall to the ground. 

Finally, we can use that time in our first kinematic equation to find the final speed of the object when it hits the ground:
V_{f}=V_{i}+gt
V_{f}=31.21+(32)(2.47)
V_{f}=110.25 ft/s

We can conclude that the speed of the object when it hits the ground is 110.25 ft/s


5 0
3 years ago
People travel from all over the world to see more than 30 glaciers at Glacier National Park in Alaska.
Whitepunk [10]
The answer I believe is c
Explanation
During the day when temperatures are higher, the snow melts and water enters the cracks in the rock. When the temperature drops below 0°C the water in the crack freezes and expands by about 9 per cent. This makes the crack larger.
3 0
3 years ago
Read 2 more answers
Categorize these resources as either renewable or Non-renewable
valentinak56 [21]

renewable: water, plants, animals

nonrenewable: rocks, soil

i hope this helps :)

5 0
3 years ago
Se coloca una piedra de 600 g en una Honda de 50 cm y se la hace girar a una velocidad de 4 m/s. Dibuja la fuerza que ejerce la
Dima020 [189]

Answer:

Fc = 19.2 N

Explanation:

In this case, the force of the Honda over the rock, is a centripetal force. Then, you have:

F_c=m\frac{v^2}{r}

m: mass of the rock = 600g = 0.6 kg

v: tangential velocity of the Honda = 4m/s

r: radius of the Honda = 50cm = 0.5m

You replace the values of m, r and v in the equation for Fc:

F_c=(0.6kg)\frac{(4m/s)^2}{0.5m}\\\\F_c=19.2N

hence, the force has a magnitude of 19.2 N

If the rock would have more mass the centripetal force would be higher

4 0
3 years ago
The work that a force does by acting on an object is equal to what?
maw [93]
2nd and only 2nd option is right
3 0
3 years ago
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