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2 years ago

10

Alguien me puede ayudar en mi examen de fisica¿ porfavor es este https://forms.office.com/Pages/ResponsePage.aspx?id=AmBpC6bWZkK

JKBXtjQZEEGFFgCLKpPRNlrCyVE_kApNUQjZRQ01NQlVSM1hFWFZTRDFFMkQ5TjU2RiQlQCNjPTEu

1 answer:

Reptile [31]2 years ago

4 0

Answer:

Chicken Feet Or Butt Whole

Explanation:

Call Me Girls!

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What is a tool that can be used to measure the size of a force

Travka [436]

The answer to this question would be: a spring scale.

The spring scale that you use to determine your body weight is actually a device that measures your body gravitational force. The force itself influenced by your body weight, that is why it can determine your body weight.
More weight means more force, more force will shrink the spring more.

7 0

3 years ago

Please help me with this

aev [14]

Answer:

the answer is UV Radiation

6 0

3 years ago

Three resistors connected in series have potential differences across them labeled /\V1 , /\V2 , and /\V3. What expresses the po

Brrunno [24]

Answer:

$\Delta V=\Delta V_1+\Delta V_2+\Delta V_3$

Explanation:

We are given that three resistors R1, R2 and R3 are connected in series.

Let

Potential difference across $R_1=\Delta V_1$

Potential difference across $R_2=\Delta V_2$

Potential difference across $R_3=\Delta V_3$

We know that in series combination

Potential difference , $V=V_1+V_2+V_3$

Using the formula

$\Delta V=\Delta V_1+\Delta V_2+\Delta V_3$

Hence, this is required expression for potential difference.

3 0

3 years ago

Consider the situation||: A child pulls a sled by a rope across the lawn at a constant speed. Of the forces listed, identify whi

Mice21 [21]

Answer:

Gravitational

Tension

Normal

Friction.

Explanation:

The forces acting on the sled are:

Tension: the tension from the rope, this is the force that "moves" the sled.

Friction: kinetic friction between the sled and the ground as the sled moves.

There are another two forces that also act on the sled, but that "has no effect"

Gravitational force: This force pulls the sled down, against the floor.

Normal force: This force "opposes" to the gravitational one, so they cancel each other.

These two forces cancel each other, so they have no direct impact on the movement of the sled. BUT, the friction force depends on the weight of the moving object, and the weight of the moving object depends on the gravitational force, so we need gravitational force in order to have friction force.

Then we can conclude that the forces acting on the sled are:

Gravitational

Tension

Normal

Friction.

6 0

2 years ago

An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary

Alenkinab [10]

Answer:

T = 4200N

Explanation:

When the submersible craft is at rest, the tension in the cable is 6000N.

With this information you can calculate the weight of the craft by summing the forces (the summation of the force is zero because the craft is at rest):

$T-W=0\\\\W=T=6000N$

When the craft is going down with a constant speed, there is a drag force of 1800N. Then, by using the second Newton law you have:

$T-W+F_d=0$ (1)

Fd: drag force

The summation of the forces is zero because the craft moves with constant velocity, that is, there is no acceleration.

You calculate the new tension on the cable by solving the equation (1) for T:

$T=W-Fd=6000N-1800N=4200N$

hence, the tension is 4200N

5 0

3 years ago