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AleksandrR [38]
3 years ago
6

Two of the most expensive cars in the world are car A and car B. The prices of these two cars differ by more than $15,000. The p

rice of car A is $131,745. a. Assuming that you do not know which model is more expensive, write an absolute value in equality that describes this situation. Use x for the cost of car B. b. What are the possibilities for the price of car B?
Mathematics
1 answer:
Nina [5.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

Part a:

Price of car A = $131,745    and price of car B is unknown = x

There are two possible cases: 1) Car A is the more expensive car, and 2) car B is the more expensive one. We start by analyzing both cases separately:

Case 1) If car A is the more expensive car, we could write the difference in prices in mathematical form, using the "larger than" symbol: ">"

$131,745 - x > $15,000 that reads :"the price of car A ($131,745) minus the price of car B (x) is MORE THAN (>) $15,000

Case 2) Car B is more expensive than A, so we can write:

x - $131,745 > $15,000 that reads: "the price of car B (x) minus the price of car A ($131,745) is MORE THAN (>) $15,000

Both inequalities that we wrote above can be condense in a single inequality if we use the "absolute value" mathematical symbol thus expressing that the difference between both prices in absolute value must be larger than $15,000:

| $131,745 - x | > $15,000

Part b) We can solve for x in the first inequality we wrote:

$131,745 - $15,000 > x therefore x < $116,745

and also we can solve for x in the second inequality given us the second possibility:

x - $131,745 > $15,000  therefore x > $146,745

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Juan starts walking at 4 miles per hour. An hour and a half later, Cathy starts jogging along the same route at 7 miles per hour
kifflom [539]

Answer:

The answer to your question is 2 hours

Step-by-step explanation:

Data

Juan speed = 4 mi/h

Cathy speed = 7 mi/h

t = x

Formula

speed = distance/time

Solve for distance

distance = speed x time

           d = s x t

Distance travelled by Juan

          d = 4t

Distance travelled by Juan in 1.5 h

         d = 4(1.5)

         d = 6 mi

total distance    d = 6 + 4t

Distance travelled by Cathy

         d = vt

         d = 7t

Equal both equations

         6 + 4t = 7t

Solve for t

         6 = 7t - 4t

         6 = 3t

         6/3 = t

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Cathy wll catch up with Juan in 2 hours

6 0
4 years ago
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What is 5280 divided by 60
Daniel [21]

Answer:

ya the answer is 88

Step-by-step explanation:

4 0
3 years ago
If a model scale is 1 foot to 5 feet, how long will the model be
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adelina 88 [10]

Answer:

\sigma = 12.5 ---- sample standard deviation

\sigma^2 = 157.2 ---- sample variance

Step-by-step explanation:

Solving (a): The sample variance

First, we calculate the midpoint of each class (this is the average of the limits)

So, we have:

x_1 = \frac{56 + 64}{2} = 60

x_2 = \frac{65 + 73}{2} = 69

And so on

So, the table becomes:

\begin{array}{cc}{x} & {f} & {60} & {11} & {69} & {15} & {78} & {14} & {87} & {4} & {96} & 11 \ \end{array}

Calculate the mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{60*11+69*15+78*14+87*4+96*11}{11+15+14+4+11}

\bar x = \frac{4191}{55}

\bar x = 76.2

The variance is:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}

So, we have:

\sigma^2 = \frac{(60 - 76.2)^2*11+(69 - 76.2)^2*15+(78 - 76.2)^2 *14+(87 - 76.2)^2*4+(96 - 76.2)^2*11}{11+15+14+4+11-1}

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The sample standard deviation is:

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To find the median cancel out numbers on both sides, until one is left in the middle and if there are two in the middle add them up and divide by two. 

So in this case the median is 
53+78
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65.5
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3 years ago
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