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2 years ago

A number k is more than 4 and less than 10.

Mathematics

1 answer:

Digiron [165]2 years ago

3 0

its has to be 5,6,7,8,9

Step-by-step explanation:

it has to be more than 4 and less than 10

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Nine less than one forth of a number is 6

snow_lady [41]

Answer:

$x = 60$

Step-by-step explanation:

Step 1: Convert into an equation

Nine less than one forth of a number is 6

$1/4x - 9 = 6$

Step 2: Add 9 to both sides

$1/4x - 9 = 6$

$1/4x - 9 + 9= 6+ 9$

$1/4x = 15$

Step 3: Multiply both sides by 4

$1/4x * 4 = 15 * 4$

$x = 60$

Answer: $x = 60$

6 0

1 year ago

3^x=1÷3. Write down the value of x

Tatiana [17]

Answer:

x = -1

Step-by-step explanation:

3^x = 1/3

3^x= 3^-1

x=-1

6 0

2 years ago

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Find the area of the kite with diagonals a= 12 and b=9

Gnoma [55]

maybe 108 is the answer.

4 0

2 years ago

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Which is 2logx - 6 log(x-9) written as a single logarithm.

Anton [14]

Answer: option c

Step-by-step explanation:

To solve this problem you must keep on mind the properties of logarithms:

$log(b)-log(a)=log(\frac{b}{a})\\\\log(b)+log(a)=log(ba)\\\\a*log(b)=log(b)^a$

Therefore, knowing the properties, you can write the expression gven in the problem as shown below:

$2logx-6log(x-9)\\logx^2-log(x-9)^6\\\\log\frac{x^2}{(x-9)^6}$

5 0

2 years ago

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Sec theta - Csc theta / (csc theta)(sec theta)

Sophie [7]

Answer:

sin(x)-cos(x)

Step-by-step explanation:

$\frac{\frac{1}{cos(x)} - \frac{1}{sin(x)} }{\frac{1}{sin(x)} * \frac{1}{cos(x)} }$

Simplify the denominator:

$\frac{\frac{1}{cos(x)} - \frac{1}{sin(x)} }{\frac{1}{cos(x)sin(x)} }$

Simplify the numerator:

$\frac{{\frac{2(sin(x)-cos(x))}{sin(2x)} } }{\frac{1}{sin(x)} * \frac{1}{cos(x)} }$

Divide the fractions: (a/b)/(c/d) = (a * d)/(b * c):

$\frac{(-cos(x)+sin(x))*2cos(x)sin(x)}{sin(2x)}$

Use the identity: 2cos(x)sin(x) = sin(2x):

$\frac{sin(2x)(-cos(x)+sin(x))}{sin(2x)}$

Cancel out the common factor (sin(2x)):

-cos(x) + sin(x)

Simplify:

sin(x) - cos(x)

3 0

2 years ago

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