Answer:
Answer is provided in the explanation section
Explanation:
Convert 8-bit 2’s complement form into 16-bit 2’s complement form.
First write value in binary then check for 8 th bit value. If it is positive the upper 8 bits will be zero otherwise will be 1s.
8-bit number Binary of number Insert 8 bits 16-bit number
0X94 1001-0100 1111-1111-1001-0100 0XFF94
0XFF 1111-1111 1111-1111-1111-1111 0XFFFF
0X23 0010-0011 0000-0000-0010-0011 0X0023
0XBC 1011-1100 1111-1111-1011-1100 0XFFBC
Which of the following 16-bit 2’s complement form can be shortened to 8-bits?
16-bit number 8-bit number
0X00BA 0XBA
0XFF94 MSB bits are not zero so we can’t truncate it to 8-bit No
0X0024 0X24
0XFF3C MSB bits are not zero so we can’t truncate it to 8-bit No
The answer is a FRAME.
This is part of data encapsulation process. The data link layer encapsulates a packet into a frame. The
Frame’s header carries hardware address of the source and destination hosts. A
frame includes the network layer header, transport layer header and all upper
layer information.
Answer:
2910 to binary = 101101011110
2910 to hexadecimal = B5E
2910 to octal = 5536
E316 to binary = 1110001100010110
E316 to octal = 161426
E316 to decimal = 58134
5916 to binary = 101100100010110
5916 to decimal = 22806
5916 to octal = 54426
010010102 to decimal = 149
010010102 to octal = 225
010010102 to hexadecimal = 95
FOR 438 and 618, 8 is not a valid digit for octal..
Answer:
Business continuity
Explanation:
The disaster is affecting business functions and needs to be urgently remedied.