Answer:
You can prove this statement as follows:
Step-by-step explanation:
An odd integer is a number of the form
where
. Consider the following cases.
Case 1. If
is even we have:
.
If we denote by
we have that
.
Case 2. if
is odd we have:
.
If we denote by
we have that 
This result says that the remainder when we divide the square of any odd integer by 8 is 1.
-3(2x-4)+8x-8
-6x+12+8x-8
2x+4
x=2
The given statement is false because it isn't an empty set!
<u>Step-by-step explanation:</u>
We have following sets of inequalities:

From
we get ,

Therefore solution set is x=2.
Now, for
we get ,

Therefore solution set is x>2.
For
we get ,

Therefore solution set is x<2.
Now, the union of x=2, x<2 & x>2 is -∞<x<∞. i.e. all possible values of x. And so above statement is false because it isn't an empty set!
Answer:
see below
Step-by-step explanation:
y = 5x-3
Let x = -2 y = 5(-2) -3 = -10 -3= -13
Let x = -1 y = 5(-1) -3 = -5-3 = -8
Let x = 0 y = 5(0) -3 = 0-3 = -3
Let x = 1 y = 5(1) -3 = 5-3 = 2
Let x = 2 y = 5(2) -3 =10-3 = 7
Answer:
View picture for answer.
Step-by-step explanation: