All categories

3 years ago

Pedro gets 8 hours of sleep each night.how many hours does pedro sleep in a year with 365 days

Mathematics

2 answers:

stepladder [879]3 years ago

6 0

365 times 8 = 2920 hr of sleep in a year

igor_vitrenko [27]3 years ago

3 0

Answer:

Number of hours pedro sleep in a year 2,920 hours

Step-by-step explanation:

Pedro gets 8 hours of sleep each night.

So, 1 year = 365 days = 365 nights.

To find the number of hours sleep in a year, we need to multiply 365 by 8.

Number of hours pedro sleep in a year = 365 × 8 hours = 2,920 hours

You might be interested in

What is the coefficient of the variable in the expression 4 − 3x − 7 + 6?

liberstina [14]

-3.

Coefficients are numbers that have a variable next to it, thus leading it to be -e of the -3x.

Hope this helps!

3 0

4 years ago

Read 2 more answers

Which is the approximate measure of angle Y? Use the law of sines to find the answer.

vitfil [10]

Siny/2.7=sin63/2.8

siny=2.7sin63/2.8

y=arcsin((2.7sin63)/2.8)

y≈59.23° (to nearest one-hundredth of a degree)

8 0

3 years ago

Read 2 more answers

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

sergiy2304 [10]

Answer:

(a) P(X=3) = 0.093

(b) P(X≤3) = 0.966

(c) P(X≥4) = 0.034

(d) P(1≤X≤3) = 0.688

(e) The probability that none of the 25 boards is defective is 0.277.

(f) The expected value and standard deviation of X is 1.25 and 1.089 respectively.

Step-by-step explanation:

We are given that when circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%.

Let X = the number of defective boards in a random sample of size, n = 25

So, X ∼ Bin(25,0.05)

The probability distribution for the binomial distribution is given by;

$P(X=r)= \binom{n}{r} \times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,......$

where, n = number of trials (samples) taken = 25

r = number of success

p = probability of success which in our question is percentage

of defectivs, i.e. 5%

(a) P(X = 3) = $\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $2300 \times 0.05^{3}\times 0.95^{22}$

= 0.093

(b) P(X $\leq$ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}+\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $1 \times 1 \times 0.95^{25}+25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.966

(c) P(X $\geq$ 4) = 1 - P(X < 4) = 1 - P(X $\leq$ 3)

= 1 - 0.966

= 0.034

(d) P(1 ≤ X ≤ 3) = P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.688

(e) The probability that none of the 25 boards is defective is given by = P(X = 0)

P(X = 0) = $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}$

= $1 \times 1\times 0.95^{25}$

= 0.277

(f) The expected value of X is given by;

E(X) = $n \times p$

= $25 \times 0.05$ = 1.25

The standard deviation of X is given by;

S.D.(X) = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{25 \times 0.05 \times (1-0.05)}$

= 1.089

8 0

3 years ago

Find 4 consecutive intergers such that the sum of the secound and forth is 34

ankoles [38]

Consecutive integers are 1 aparrt
they are
x,x+1,x+2,x+3

the 2nd and 4th sum is x+1 and x+3
sum is 34
x+1+x+3=34
2x+4=34
minus 4
2x=30
divide 2
x=15

x+1=16
x+2=17
x+3=18

the numbers are 15,16,17,18

4 0

3 years ago

What is the y- intercept of: y=-2x

shusha [124]

Answer:

it is Zero 0

Step-by-step explanation:

7 0

3 years ago