Neither collinear nor coplanar.
All of the points would have to be on the same line to make them collinear, and they would also have to be on the same plane to make them coplanar. We can see in the diagram that not all of the points are on a line, and that some are at different heights than others.
The line crosses points (0, -1) and (2, 0)
y - (-1) = (0 - (-1))/(2 - 0) (x - 0)
y + 1 = 1/2 x
y = 1/2x - 1
yes it does have enough to cover the cube
Answer: b
Step-by-step explanation:
Graph the equation in a graphing calculator or in the table in a regular calculator and look for the zero on the x axis and the y axis
