Answer:
The entropy change for a real, irreversible process is equal to <u>zero.</u>
The correct option is<u> 'c'.</u>
Explanation:
<u>Lets look around all the given options -:</u>
(a) the entropy change for a theoretical reversible process with the same initial and final states , since the entropy change is equal and opposite in reversible process , thus this option in not correct.
(b) equal to the entropy change for the same process performed reversibly ONLY if the process can be reversed at all. Since , the change is same as well as opposite too . Therefore , this statement is also not true .
(c) zero. This option is true because We generate more entropy in an irreversible process. Because no heat moves into or out of the surroundings during the procedure, the entropy change of the surroundings is zero.
(d) impossible to tell. This option is invalid , thus incorrect .
<u>Hence , the correct option is 'c' that is zero.</u>
C - bc as the water boils the cold water particles melt and become the hot water particles!
Answer:
- Increased volume of particles in the container
- greater vibration of particles
Explanation:
At higher temperature, the particles of the gas would be more active and vibrate more, or even have greater collisions. Alex can indicate this in the altered model to depict higher temperature.
Consequently, Charles law gives meaning to why there would be an increased volume of gas in the stable pressurized container, if the temperature were to be increased.
I hope this explanation was clear and concise?
12+70= 82 g
(12/82)x100 = 14.6%
The answer is given to one decimal place.
