I know the answer. It is 2 straight chains. lLOL
40.6 kJ of heat energy had been emitted.
CO(g) + 2H2(g) CH3OH(l)CO volume, V (CO), equals 15 L or 0.015 m3.
Temperature = 85 0C = 85 + 273 = 358 K Pressure = 112 kPa = 112,000 PaPV = nRT n= 112000 0.015 / 8.314 358 n(CO) = 0.56 moles,
according to the ideal gas law.H2 volume is 14.4 L or 0.0144 m3
T = 750C + 273 K = 348 K n(H2) = 99191.84 0.0144 m3 / 8.314 348 K = 0.49 moles of H2 Pressure = 744 torr = 99191.84 Pa
Hydrogen is the limiting reagent, according to the calculation above.CH3OH = H2 = 0.49/2 = 0.245 m-238.6 (-110.5) = -128.1 kJ/mol for H(rxn) = H(f) (CH3OH) - H (rxn)
We must now multiply H(rxn) by the number of moles of methanol.
E = H(rxn) n(CH3OH) = 128.1 0.245 = 40.6 kJ.
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Answer:
Inactive metals are inert metals that doesn’t react with most of the chemicals.They are highly resistant to oxidation and corrosion when exposed to moisture.
Explanation:
