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harina [27]
3 years ago
12

If a substance increases the OH- concentration of pure water by 10^4. what is the pH of the solution?

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

pH = 11

Explanation:

The concentration of OH⁻ in <em>pure water</em> is 10⁻⁷ M. If a substance increases OH⁻ concentration by 10⁴, the new concentration will be:

[OH⁻] = 10⁴ x 10⁻⁷ M = 10⁻³M

We can calculate pOH using it's definition:

pOH = -log[OH⁻] = -log (10⁻³) = 3

Then, we can find out pH using the following relation:

pH + pOH = 14

pH = 14 - pOH = 14 -3 = 11

Since pH = 11 is higher than 7, we can confirm that the substance is a base.

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