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Shalnov [3]
4 years ago
10

Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system,

based on the following descriptions:
Surroundings get colder and the system decreases in volume.
Surroundings get hotter and the system expands in volume.
Surroundings get hotter and the system decreases in volume.
Surroundings get hotter and the system does not change in volume.

A mole of X reacts at a constant pressure of 43.0 atm via the reaction.

X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ

Also assume that the magnitude of the volume and temperature changes are similar among the reactions. Rank from most energy released to most energy absorbed. To rank items as equivalent, overlap them. View Available Hint(s)
Chemistry
1 answer:
galina1969 [7]4 years ago
6 0

Answer:

The options are

A.Surroundings get colder and the system decreases in volume.

B.Surroundings get hotter and the system expands in volume.

C.Surroundings get hotter and the system decreases in volume.

D.Surroundings get hotter and the system does not change in volume.

From the Most energy released to the most absorbed , the order is

B. Surroundings get hotter and the system expands in volume.

D. Surroundings get hotter and the system does not change in volume.

C. Surroundings get hotter and the system decreases in volume.

A. Surroundings get colder and the system decreases in volume.

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4. A 14.5-L balloon is in the air where it is 20.0 C at 0.980-atm. A wind passes over and the balloon's pressure becomes 740.0-m
jeka94

The temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

<h3>What is Combined gas law?</h3>

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 14.5L
  • Initial pressure P₁ = 0.980atm
  • Initial temperature T₁ = 20.0°C = 293.15K
  • Final volume V₂ = 14.3L
  • Final pressure P₂ = 740.mmHg = 0.973684atm
  • Final temperature T₂ = ?

We substitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

( 0.980atm × 14.5L )/293.15K = ( 0.973684atm × 14.3L )/T₂

14.21Latm / 293.15K = 13.92368Latm / T₂

14.21Latm × T₂ = 13.92368Latm × 293.15K

14.21Latm × T₂ = 4081.72679LatmK

T₂ = 4081.72679LatmK / 14.21Latm

T₂ = 287.24K

T₂ = 14.09°C

Therefore, the temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

Learn more about the combined gas law here: brainly.com/question/25944795

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