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Bogdan [553]
4 years ago
6

Where does the process of cellular respiration mostly happen?

Chemistry
1 answer:
ExtremeBDS [4]4 years ago
3 0

It mostly begins in the cytoplasm, but most of the reactions occur in the cell mitochondria.

Hope this helps, if not, comment below please!!!!

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A student is given the following information about an unknown solution:
Harlamova29_29 [7]

Answer:

answer is strong base hope it helps

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3 years ago
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How many moles of NO2 form when<br> 63.25 g N2O5 decompose?<br><br> 2N₂O54NO₂ + O₂
KonstantinChe [14]

Answer:

1.1713 moles

Explanation:

RFM of N2O5=108

Moles of N2O5= mass/RFM= 63.25/108=0.5856 moles

Mole ratio of N2O5:NO2= 2:4

Therefore moles of NO2= 4/2*0.5856= 1.1713 moles

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2 years ago
In an ion with an unknown charge, the total mass of all the electrons was determined to be 1.640 x <img src="https://tex.z-dn.ne
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luda_lava [24]

The sum is 34.688 m.

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3 years ago
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Sugar is easily soluble in water and has a molar mass of 342.30 g/mol. what is the molar concentration of a 252.6 ml aqueous sol
lions [1.4K]

0.811 M is the molar concentration of a 252.6 ml aqueous solution prepared with 70.3 g of sugar.

<h3>Define molarity of a solution.</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Given data:

252.6 mL = 0.2526 L

Next, we shall determine the number of moles of the sugar. This can be obtained as follow:

Molar mass of sugar = 342.30 g/mol.

Mass of sugar = 70.3 g

Mole of sugar =?

Mole =\frac{mass}{molar \;mass}

Mole =  \frac{70.3 g}{342.30}

Mole of sugar = 0.205 mole

Finally, we shall determine the molar concentration of the sugar. This can be obtained as follow:

Mole of sugar = 0.205 mole

Volume =  0.2526 L

Molarity =?

Molarity = \frac{Moles \;solute}{Volume of solution in litre}

Molarity = \frac{0.205 mole}{ 0.2526 L}

Molarity = 0.811 M

Therefore, the molar concentration of the solution is 0.811 M

Learn more about molarity here:

brainly.com/question/2817451

#SPJ1

8 0
2 years ago
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