The answer would be: <span>a.a mixture that is uniform throughout
A homogenous mixture would be hardly distinguishable since the solute spread evenly inside the solvent. A heterogeneous mixture is not spread evenly so it is </span>easily distinguishable.A suspension has a big molecule solute that will slowly settle and make sediment at the base of the solution. A colloid mixture is suspended but it won't settle like suspension does.
Answer:
P2 = 2.25 atm
Explanation:
Given:
V1 = 1.5 L. V2 = 2.0 L
P1 = 3.0 atm. P2 = ?
Use Boyle's law and solve for P2:
P1V1 = P2V2
or
P2 = (V1/V2)P1
= (1.5 L/2.0L)(3.0 atm)
= 2.25 atm
Answer:
∆H= <u>438 KJ/mol</u>
Explanation:
First, we have to find the <u>energy bond values</u> for each compound:
-) Cl-Cl = 243 KJ/mol
-) F-F = 159 KJ/mol
-) F-Cl = 193 KJ/mol
If we check the reaction we can calculate the <u>number of bonds</u>:
In total we will have:
-) Cl-Cl = 1
-) F-F = 3
-) F-Cl = 6
With this in mind. we can calculate the <u>total energy for each bond</u>:
-) Cl-Cl = (1*243 KJ/mol) = 243 KJ/mol
-) F-F = (3*159 KJ/mol) = 477 KJ/mol
-) F-Cl = (6*193 KJ/mol) = 1158 KJ/mol
Now, we can calculate the total energy of the <u>products</u> and the <u>reagents</u>:
Reagents = 243 KJ/mol + 477 KJ/mol = 720 KJ/mol
Products = 1158 KJ/mol
Finally, to calculate the total enthalpy change we have to do a <u>subtraction</u> between products and reagents:
∆H= 1158 KJ/mol-720 KJ/mol = <u>438 KJ/mol</u>
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I hope it helps!
Answer:
n = 1.3 x 10¹⁸ photons
Explanation:
First we need to calculate the amount of energy released in given time:
E = Pt
where,
E = Energy = ?
P = Power = 4 mW = 0.004 W
t = time = 115 s
Therefore,
E = (0.004 W)(115 s)
E = 0.46 J
Now, this energy can be given in forms of photons as:
E = nhc/λ
where,
n = No. of photons = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light = 5650 x 10⁻¹⁰ m
Therefore,
0.46 J = n(6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(5650 x 10⁻¹⁰ m)
n = (0.46 J)/(3.5 x 10⁻¹⁹ J)
<u>n = 1.3 x 10¹⁸ photons</u>