2 Corsls provide treatments
Assuming it is complete combustion, the products would be
CO2 and H2O.
We must have a balanced equation,
C6H6 + (15/2)O2 -> 6CO2 + 3H2O
This means 1 mol C6H6 yields 6 mol CO2
5.45 mol C6H6 ( 6 mol CO2 / 1 mol C6H6) = 32.7 mol CO2
Answer:
57.2 g
Explanation:
First we <u>convert 66.4 grams of Ba(ClO₄)₂·3H₂O into moles</u>, using its <em>molar mass</em>:
- Molar mass of Ba(ClO₄)₂·3H₂O = Molar mass of Ba(ClO₄)₂ + (Molar Mass of H₂O)*3
- Molar mass of Ba(ClO₄)₂·3H₂O = 390.23 g/mol
- 66.4 g ÷ 390.23 g/mol = 0.170 mol Ba(ClO₄)₂·3H₂O
0.170 moles of Ba(ClO₄)₂·3H₂O would produce 0.170 moles of 0.170 moles of Ba(ClO₄)₂. Meaning we now <u>convert 0.170 moles of Ba(ClO₄)₂ into grams,</u> using the molar mass of Ba(ClO₄)₂:
- 0.170 mol * 336.23 g/mol = 57.2 g
Answer:
wait what? is this a homework question?
Answer:
? the question isn't clear
Explanation: