Question

Sugar is easily soluble in water and has a molar mass of 342.30 g/mol. what is the molar concentration of a 252.6 ml aqueous solution prepared with 70.3 g of sugar?

Answer 1

0.811 M is the molar concentration of a 252.6 ml aqueous solution prepared with 70.3 g of sugar.

Define molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Given data:

252.6 mL = 0.2526 L

Next, we shall determine the number of moles of the sugar. This can be obtained as follow:

Molar mass of sugar = 342.30 g/mol.

Mass of sugar = 70.3 g

Mole of sugar =?

Mole =$\frac{mass}{molar \;mass}$

Mole =  $\frac{70.3 g}{342.30}$

Mole of sugar = 0.205 mole

Finally, we shall determine the molar concentration of the sugar. This can be obtained as follow:

Mole of sugar = 0.205 mole

Volume =  0.2526 L

Molarity =?

Molarity = $\frac{Moles \;solute}{Volume of solution in litre}$

Molarity = $\frac{0.205 mole}{ 0.2526 L}$

Molarity = 0.811 M

Therefore, the molar concentration of the solution is 0.811 M

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