It’s some apps that come in handy for this sorry if I didn’t help
First write the formula and make sure it is balance
MgSO4 + BaCl2 --> MgCl2 + BaSO4
then, we need to determine which reactant is the limiting reagent. using their respective molar masses.
1.20 g MgSO4 x (1 mole MgSO4/ 120.3 g)=0.00998 moles
10.0 g BaCl2 x (1 mole BaCl/ 172 g) = 0.0580 moles
Since MgSO4 give the less amount of moles, MgSO4 is the limiting reagent.
0.00998 moles MgSO4 (1 mole BaSO4/1 mole MgSO4) (233.3 g/ 1 mole BaSO4) = 2.34 grams
Answer:
Theoretical yield is 138.4 g
Explanation:
In the first step we determine the reaction:
3Mg + N₂ → Mg₃N₂
Mass of reactant is 100 g. We assume the nitrogen is in excess, so we work with Mg. We convert mass to moles:
100 g . 1mol/ 24.3g = 4.11 moles of Mg.
Ratio is 3:1. 3 moles of Mg can produce 1 mol of nitride
Our 4.11 moles, may produce (4.11 . 1)/3 = 1.37 moles of Mg₃N₂
We convert mass to moles, to find the theoretical yield:
1.37 mol . 100.9 g/mol = 138.2 g
Answer:
921.8207 mL
Explanation:
(V1 / T1) = (V2 / T2)
add 273 to each °C in the problem to make them in kelvin
(693 / 318) = (X / 423)
solve for X
X = 921.8207 mL
Answer:
Rule, oversee, discipline
Explanation:
hope it helped!