Answer:
Mass = 11.16 g
Explanation:
Given data:
Mass of hydrogen = 8 g
Mass of oxygen = 10 g
Mass of water produced = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass / molar mass
Number of moles = 8 g/ 2 g/mol
Number of moles = 4 mol
Number of moles of oxygen:
Number of moles = mass / molar mass
Number of moles = 10 g/ 32 g/mol
Number of moles = 0.31 mol
now we will compare the moles of hydrogen and oxygen with water.
O₂ : H₂O
1 : 2
0.31 : 2/1×0.31 = 0.62
H₂ : H₂O
2 : 2
4 : 4
Number of moles of water formed by oxygen are less this it will act as limiting reactant.
Mass of water:
Mass = number of moles × molar mass
Mass = 0.62 mol × 18 g/mol
Mass = 11.16 g
Answer:
6.25×10⁻⁶ g / cm³
Explanation:
Density is the relation between mass and volume as this formula shows.
Density of a compound = Mass of the compound / Volume of compound
In the values, we were given:
0.0124 kg / 1983 mm³ = 6.25×10⁻⁶ kg/mm³
This number means that in a volume of 1 mm³ of compound, the mass of it occupies 6.25×10⁻⁶ kg. Let's make a rule of three:
1 cm³ = 1×10⁻³ mm³
In 1 mm³ we have 6.25×10⁻⁶ kg of compound
So in 1×10⁻³ mm³ we would have (1×10⁻³ mm³ . 6.25×10⁻⁶ kg) / 1 mm³ =
6.25×10⁻⁹ kg
Now let's convert the kg to g.
1 kg = 1000 g
6.25×10⁻⁹ kg . 1000 = 6.25×10⁻⁶ g
Finally density is : 6.25×10⁻⁶ g / cm³
Answer:
H3PO4 + 5 HCl → PCl5 + 4 H2O
Explanation:
The given equation is
H3PO4 + HCl = PCl5 + H2O
The above chemical equation has one P atom on both the sides, hence phosphorus is balanced
There are 5 Cl on the RHS but only one Cl on the LHS. On balancing the chlorine, we get -
H3PO4 + 5HCl = PCl5 + H2O
Now, there are 8 hydrogen atom on the LHS but only two on the RHS. On balancing the hydrogen on both the sides, the new equation become
H3PO4 + 5HCl = PCl5 + 4H2O
Let us check for oxygen
Oxygen on LHS = 4 and oxygen on RHS = 4
Thus, the balanced equation is H3PO4 + 5HCl = PCl5 + 4H2O
