Medium about 3 second? Not sure lol just need more points honestly lol
You may find bellow the balanced chemical equations.
Explanation:
Molecular equations:
3 Sr(NO₃)₂ (aq) + 2 K₃PO₄ (aq) → Sr₃(PO₄)₂ (s) + 6 KNO₃ (aq)
2 NaOH (aq) + Ni(NO₃)₂ (aq) = Ni(OH)₂ (s) + 2 NaNO₃ (aq)
Ionic equations:
3 Sr²⁺ (aq) + 6 NO₃⁻ (aq) + 6 K⁺ (aq) + 2 PO₄³⁻ (aq) → Sr₃(PO₄)₂ (s) + 6 K⁺ (aq) + 6 NO₃⁻ (aq)
2 Na⁺ (aq) + 2 OH⁻ (aq) + Ni²⁺ (aq) + 2 NO₃⁻ (aq) = Ni(OH)₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)
To get the net ionic equation we remove the spectator ions:
3 Sr²⁺ (aq) + 2 PO₄³⁻ (aq) → Sr₃(PO₄)₂ (s)
2 OH⁻ (aq) + Ni²⁺ (aq) = Ni(OH)₂ (s)
Learn more about:
net ionic equations
brainly.com/question/7018960
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The concentration in mol/l of reactant after 1.5 s is calculated as follows
from first order integrated equation
In (A)t = - Kt + In (A)o where
At = final concentration =?
A)o =initial concentration =0.27 M
K = constant=0.75
T=temperature = 1.5 s
in( A)t = -0.75(1.5) + in(0.27)
In (A)t =-1.125 +-1.31 =-2.435
In(A)t =-2.435
In (A)t = e
find the e value
( A)t is therefore =0.0876 mol/l
Answer:
<em>C</em> NaOHsln = 0.125 M
Explanation:
Molarity (M) [=] mol/L
∴ moles NaOH = (0.125 L)(0.15 mol/L) = 0.01875 mol
∴ Vsln = 150 mL = 0.150 L
New Molarity:
⇒ <em>C</em> NaOH = 0.01875 mol/0.150 L
⇒ <em>C</em> NaOH = 0.125 M
Answer:
Measure so that the line you are reading is even with the center of the meniscus. For water and most liquids, this is the bottom of the meniscus. For mercury, take the measurement from the top of the meniscus. In either case, you are measuring based on the center of the meniscus.
Explanation:
