3NO2 + H2O = 2 HNO3 + NO

An atom has the following electron configuration.

Wewaii [24]

Answer: 5

Explanation: add up all the electrons and it will amount to 23. Arranging by the old model for electronic configuration, we have : 2, 8, 8, 5

The last number being 5 represent its valence electron

3 0

3 years ago

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In glycolysis, if glucose is labeled at the carbon 6 position (see page 1 for numbering of carbons in glucose) A) the carbon wit

Oliga [24]

Answer:

D) the carbon with the low-energy phosphate on it in 1,3 BPG is labeled.

Explanation:

Glycolysis has 2 phase (1) preparatory phase (2) pay-off phase.

(1) Preparatory phase

During preparatory phase glucose is converted into fructose-1,6-bisphosphate. Till this time the carbon numbering remains the same i.e. if we will label carbon at 6th position of glucose, its position will remian the same in fructose-1,6-bisphosphate that means the labeled carbon will still remain at 6th position.

When fructose-1,6-bisphosphate is further catalyzed with the help of enzyme aldolase it is cleaved into two 3 carbon intermediates which are glyceraldehyde 3-phosphate (GAP) and dihyroxyacetone phosphate (DHAP). In this conversion, the first three carbons of fructose-1,6-bisphosphate become carbons of DHAP while the last three carbons of fructose-1,6-bisphosphate will become carbons of GAP. It simply means that GAP will acquire the last carbon of fructose-1,6-bisphosphate which is labeled. Now the last carbon of GAP which has phosphate will be labeled.

(2) Pay-off phase

During this phase, GAP is dehydrogenated into 1,3-bisphosphoglycerate (BPG) with the help of enzyme glyceraldehyde 3-phosphate dehydrogenase. This oxidation is coupled to phosphorylation of C1 of GAP and this is the reason why 1,3-bisphosphoglycerate has phosphates at 2 positions i.e. at position 1 in which phosphate is newly added and position 3rd which already had labeled carbon.

It is pertinent to mention here that BPG has a mixed anhydride and the bond at C1 is a very high energy bond. In the next step, this high energy bond is hydrolyzed into a carboxylic acid with the help of enzyme phosphoglycerate kinase and the final product is 3-phosphoglycerate. Hence, the carbon with low energy phosphate i.e. the carbon at 3rd position remains labeled.

3 0

3 years ago

What is one chemical reaction that begins with petroleum as a starting material

emmasim [6.3K]

Answer:

Thermal decomposition or cracking

Explanation:

Petroleum is a mixture of hydrocarbons which are usually formed naturally. Petroleum undergo a host of chemical reactions. One of such is thermal decomposition or cracking.

Cracking is used in the petroleum industry to covert heavy fractions to more useful lighter ones.

When petroleum is subjected to high temperature and pressure, and in the presence of catalyst, the long chain type of petroleum will decompose into more useful smaller and lighter molecules.

Example is given below:

C₁₅H₃₂ → C₈H₁₈ + C₃H₆ + 2C₂H₄

6 0

3 years ago

The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

As, $K_p>>1$ , the reaction will be product favoured and as it is a acid base reaction where $HONO$ acts as acid by donating $H^+$ ions and $CN^-$ acts as base by accepting $H^+$

Thus $HONO$ is a strong acid thus $ONO^-$ will be a weak conjugate base and $CN^-$ is a strong base which has weak $HCN$ conjugate acid.

Thus the high value of K indicates that $CN^-$ is a stronger base than $ONO^-$

7 0

3 years ago

Un átomo neutro tiene número atómico 1 y número másico 3. Indica cuántos protones, neutrones y electrones tiene.

ahrayia [7]

Answer:

El átomo podes 1 protón, 1 electrón y 2 neutrones.

Explanation:

Cada elemento químico se caracteriza por el número de protones de su núcleo, que se denomina número atómico Z. Es decir, el número atómico de un elemento químico es el número total de protones que tiene cada átomo de ese elemento.

Los protones poseen carga positiva y se encuentran en el núcleo, en torno al cual se mueven otras partículas con carga eléctrica negativa que son los electrones. Así, el átomo es eléctricamente neutro, ya que la carga positiva de los protones está compensada por la carga negativa de los electrones. Entonces, en todo átomo neutro el número de protones del núcleo es igual al de electrones de sus orbitales.

En este caso, un átomo neutro tiene número atómico 1. Entonces la cantidad de protones y electrones presentes en el átomo es 1.

En el núcleo de cada elemento, además de protones, también es posible encontrar neutrones, cuyo número puede variar. La masa atómica (A) se obtiene sumando el número de protones y de neutrones de un núcleo determinado:

Número másico (A) = número de protones + número de neutrones

En este caso, el átomo neutro posee 1 protón y su número másico es 3. Entonces:

3= 1 + número de neutrones

Resolviendo:

3 - 1= número de neutrones

2= número de neutrones

Entonces, el átomo podes 1 protón, 1 electrón y 2 neutrones.

6 0

2 years ago