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Anettt [7]
3 years ago
7

the Temperature of a sample of an ideal gas in a sealed 5.0 l container is raised from 27 oC to 77oC. If the initial pressure of

the gas was 3.0 atm, what is the final pressure?
Chemistry
1 answer:
matrenka [14]3 years ago
7 0
Answer:
              The pressure increases to 3.5 atm.

Solution:
                According to Gay-Lussac's Law, " At constant volume and mass the pressure of gas is directly proportional to the applied temperature".

For initial and final states of a gas the equation is,

                                           P₁ / T₁  =  P₂ / T₂
Solving for P₂,
                                           P₂  =  P₁ T₂ / T₁    ----- (1)

Data Given;
                   P₁  =  3 atm

                   T₁  =  27 °C + 273  =  300 K
 
                   T₂  =  77 °C + 273  =  350 K

Putting values in eq. 1,

                                           P₂  =  (3 atm × 350 K) ÷ 300 K

                                           P₂  =  3.5 atm
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How many moles of O2 are needed to react completely with 35.0 mol of 10 points
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This characteristic of hydrogen and oxygen make the water molecule polar: ______.
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5 0
3 years ago
consider the titration of hclo4 with koh. what is the ph after 17.0 ml of 0.15 m koh has been added to 15 ml of 0.20 m hclo4?
bezimeni [28]

The ph after 17.0 ml of 0.15 m Koh has been added to 15 ml of 0.20 m hclo4 is  <u>3.347</u>.

Titration is a commonplace laboratory technique of quantitative chemical analysis to determine the attention of an identified analyte. A reagent, termed the titrant or titrator, is ready as a trendy answer of recognized awareness and extent.

<u>Calculation:-</u>

Normality of acid                                               Normality of base

= nMV                                                                        nMV

= 1 × 0. 15 × 0.017                                              1 ×  0. 20 ×0.015 L

= 2.55 × 10⁻³                                                             = 3 × 10⁻³

The overall base will be high

net concentration = 3× 10⁻³ - 2.55 × 10⁻³

                             = 0.45 × 10⁻³

                             = 4.5× 10⁻⁴

pH = -log[4.5 × 10⁻⁴]

    = 4 - log4.4

     = <u>3.347</u>

A titration is defined as 'the manner of determining the amount of a substance A by using adding measured increments of substance B, the titrant, with which it reacts till precise chemical equivalence is completed the equivalence factor.

Learn more about titration here:-brainly.com/question/186765

#SPJ4

7 0
1 year ago
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