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viktelen [127]
3 years ago
8

How many silver atoms are in 1 mole of silver?

Chemistry
2 answers:
never [62]3 years ago
7 0

Answer:

6.022 x 10^23

Explanation:

The number of atoms in one mole of a  substance is equal to Avogadro's number, or 6.022 x 10^23.

So, calculating the number of silver atoms in one mole of silver is simple, it is just equal to Avogadro's number, 6.022 x 10^23.

Let me know if this helps!

jekas [21]3 years ago
5 0

Answer:

Explanation:

Silver has a molar mass of 107.87 g⋅mol−1 . What does this mean? It means that if I have such a mass of silver, there are Avogadro's number, NA=6.022×1023 , individual silver atoms

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Two identical 732.0 L tanks each contain 212.0 g of gas at 293 K, with neon in one tank and nitrogen in the other. Based on the
Vladimir [108]

Answer: (a) Neon, Nitrogen; (b) Neon, Nitrogen; (c) Neon is lower than Nitrogen; (d) It doesn't affect;

Explanation: The kinetic-molecular theory studies the behavior of particles under pre-determinated situation. In cases of gases, the particles moving around colliding with each other and the walls of the container, without loss of energy. In the case in question, all the parameters are the same (same temperature, volume and pressure), except for the gases, which has different molar masses. In this sense, Neon has lower average speed due to its molar mass being higher, which means, its particles moves slower for being heavier. Related to pressure, as velocity is lower, it collides less with the walls of the tank, and so pressure is lower. For density, it doesn't affect the behavior of the system nor the kinetic energy.

7 0
3 years ago
The pathway by which carbon is transferred from living organisms to the atmosphere is called:
Phoenix [80]

Answer:

cellular respiration

Explanation:

All exergonic processes produced in the cell, through which substances oxidize and chemical energy is released, are grouped under the name of cellular respiration, but to break down an organic molecule the cells employ, mainly dehydrogenations that can be carried carried out in the presence or absence of atmospheric O2 oxygen. There are therefore two types of breathing: aerobic respiration and anaerobic respiration. The latter also called fermentation.

Aerobic respiration  (oxidative phosphorylation)

- Use molecular O2.

- It degrades glucose to CO2 and H2O

- Exergonic

- Recovers about 50% of chemical energy

- Present in most organisms.

- It uses enzymes located in the mitochondria.

3 0
3 years ago
How many molecules are contaiined in 125 grams of water, H2O?
vladimir1956 [14]

Answer:

Water has a molar mass of 18.015 g/mol . This means that one mole of water molecules has a mass of 18.015 g . So, to sum this up, 6.022⋅1023 molecules of water will amount to 1 mole of water, which in turn will have a mass of 18.015 g . 2.7144moles H2O ⋅6.022⋅1023molec.

Explanation:

7 0
2 years ago
Please help me!!!!!
kvasek [131]

election circles the nucleus

6 0
2 years ago
A mixture of 14.2 g of H2 and 36.7 g of Ar is placed in a 100.0 L container at
TiliK225 [7]

a) The total pressure of the system is  1.79 atm

b) The mole fraction and partial pressure of hydrogen is  0.89 and 1.59 atm respectively

c) The mole fraction and the partial pressure  of argon is 0.11 and 0.19 atm.

<h3>What is the total pressure?</h3>

We know tat we can be able to obtain the total pressure in the system by the use of the ideal gas equation. We would have from the equation;

PV = nRT

P = pressure

V = volume

n = Number of moles

R = gas constant

T = temperature

Number of moles of hydrogen = 14.2 g/2g = 7.1 moles

Number of moles of Argon = 36.7 g/40 g/mol

= 0.92 moles

Total number of moles =  7.1 moles + 0.92 moles = 8.02 moles

Then;

P = nRT/V

P = 8.02 * 0.082 * 273/100

P = 1.79 atm

Mole fraction of hydrogen = 7.1/8.02 = 0.89

Partial pressure of hydrogen =  0.89 * 1.79 atm

= 1.59 atm

Mole fraction of argon = 0.92 / 8.02

= 0.11

Partial pressure of argon = 0.11  *  1.79 atm

= 0.19 atm

Learn more about partial pressure:brainly.com/question/13199169

#SPJ1

3 0
1 year ago
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