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Misha Larkins [42]
3 years ago
11

What is the difference between single, double, and triple covalent bonds? How many shared electrons are in each?

Chemistry
2 answers:
defon3 years ago
7 0

Answer:

The single covalent bond is represented by a single ' - ' and it has 2 shared electrons from the the bonding atoms.

Double covalent bond is denoted with '=' and it has 4 shared electrons

Triple covalent bond is denoted by ' _=' and it has 6 shared electrons

Explanation:

In single covalent bond each participating atom contributes one electron each to be equally shared between them in order to form a single covalent bond. Thus a single covalent bond is formed when atoms share 2 electrons together

The double covalent bond is formed when each participating atom contributes two electrons each to be equally shared between them in order to form a double covalent bond. Thus a double covalent bond results from the sharing of 4 electrons together by two atoms. For example the formation of oxygen gas molecule

In triple covalent bonds, 6 electrons are shared and each pair of electrons forms a bond which results in triple covalent bonds. Each atom contributes 3 electrons for equal sharing.

lana66690 [7]3 years ago
4 0

Answer

A *single covalent bond* is formed by sharing one pair of valence electrons.They are less reactive comparatviely and have a high bond length

A *double covalent bond* is formed by sharing two pairs of valence electrons.They are moderately reactive and have moderate bond length.

A *triple covalent bond* is formed by sharing three pairs of valence electrons.They are highly reactive and have a low bond length.

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Suppose a group of volunteers is planning to build a park near a local lake. The lake is known to contain low levels of arsenic
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Answer:

A) 10.75 is the concentration of arsenic in the sample in parts per billion .

B) 7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C) It will take 1.37 years to remove all of the arsenic from the lake.

Explanation:

A) Mass of arsenic in lake water sample = 164.5 ng

The ppb is the amount of solute (in micrograms) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

\text{ppb}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^9

Both the masses are in grams.

We are given:

Mass of arsenic = 164.5 ng = 164.5\times 10^{-9} g

1 ng=10^{-9} g

Volume of the sample = V = 15.3 cm^3

Density of the lake water sample ,d= 1.00 g/cm^3

Mass of sample =  M = d\times V=1.0 g/cm^3\times 15.3 cm^3=15.3 g

ppb=\frac{164.5\times 10^{-9} g}{15.3 g}\times 10^9=10.75

10.75 is the concentration of arsenic in the sample in parts per billion.

B)

Mass of arsenic in 1 cm^3  of lake water = \frac{164.5\times 10^{-9} g}{15.3}=1.075\times 10^{-8} g

Mass of arsenic in 0.710 km^3 lake water be m.

1 km^3=10^{15} cm^3

Mass of arsenic in 0.710\times 10^{15} cm^3 lake water :

m=0.710\times 10^{15}\times 1.075\times 10^{-8} g=7,633,660.130 g

1 g = 0.001 kg

7,633,660.130 g = 7,633,660.130 × 0.001 kg=7,633.660130 kg ≈ 7,633.66 kg

7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C)

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

\frac{2.74}{41.90} days

Then days required to remove 7,633.66 kg of arsenic from the lake water :

=7,633.66\times \frac{2.74}{41.90} days=499.19 days

1 year = 365 days

499.19 days = \frac{499.19}{365} years = 1.367 years\approx 1.37 years

It will take 1.37 years to remove all of the arsenic from the lake.

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