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Misha Larkins [42]
3 years ago
11

What is the difference between single, double, and triple covalent bonds? How many shared electrons are in each?

Chemistry
2 answers:
defon3 years ago
7 0

Answer:

The single covalent bond is represented by a single ' - ' and it has 2 shared electrons from the the bonding atoms.

Double covalent bond is denoted with '=' and it has 4 shared electrons

Triple covalent bond is denoted by ' _=' and it has 6 shared electrons

Explanation:

In single covalent bond each participating atom contributes one electron each to be equally shared between them in order to form a single covalent bond. Thus a single covalent bond is formed when atoms share 2 electrons together

The double covalent bond is formed when each participating atom contributes two electrons each to be equally shared between them in order to form a double covalent bond. Thus a double covalent bond results from the sharing of 4 electrons together by two atoms. For example the formation of oxygen gas molecule

In triple covalent bonds, 6 electrons are shared and each pair of electrons forms a bond which results in triple covalent bonds. Each atom contributes 3 electrons for equal sharing.

lana66690 [7]3 years ago
4 0

Answer

A *single covalent bond* is formed by sharing one pair of valence electrons.They are less reactive comparatviely and have a high bond length

A *double covalent bond* is formed by sharing two pairs of valence electrons.They are moderately reactive and have moderate bond length.

A *triple covalent bond* is formed by sharing three pairs of valence electrons.They are highly reactive and have a low bond length.

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1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?
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Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

  • <u><em>We have the following data:</em></u>

Vo (initial volume) = 1.00 L  

V (final volume) = 473 mL → 0.473 L  

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)  

P (final pressure) = ? (in atm)

  • <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>

P_0*V_0 = P*V

1*1 = P*0.473

1 = 0.473\:P

0.473\:P = 1

P = \dfrac{1}{0.473}

\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}

<u><em>Answer:  </em></u>

<u><em>The new pressure of the gas is 2.11 atm  </em></u>

___________________________________

\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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