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Alexus [3.1K]
3 years ago
12

Is anyone good at chemistry if so can someone help me please ? (NO LINKS)

Chemistry
1 answer:
Oduvanchick [21]3 years ago
4 0

Strong acid + strong base = neutral salt;

strong acid + weak base = acidic salt;

weak acid + strong base = basic salt;

weak acid + weak base = it depends on the relative strength of the acid and base.

1. NaOH is a strong base; CH3COOH is a weak acid. The resulting salt, CH3COONa, will be basic (b).

2. HBr is a strong acid; NH3 is a weak base. The resulting salt, NH4Br, will be acidic (c).

3. H2SO4 is a strong acid; Ca(OH)2 is a strong base. The resulting salt, CaSO4, will be neutral (a).

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<h3><u>Answer;</u></h3>

a) It allows electrons to flow from the anode to the cathode.

<h3><u>Explanation</u>;</h3>
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7 0
3 years ago
A tank with volume of 2.4 cu ft is filled with Methane to a pressure of 1500 psia at 104 degrees F. Determine the molecular weig
Soloha48 [4]

Explanation:

It is known that equation for ideal gas is as follows.

               PV = nRT

The given data is as follows.

     Pressure, P = 1500 psia,     Temperature, T = 104^{o}F = 104 + 460 = 564 R

     Volume, V = 2.4 cubic ft,      R = 10.73 psia ft^{3}/lb mol R

Also, we know that number of moles is equal to mass divided by molar mass of the gas.

                n = \frac{mass}{\text{molar mass}}

            m = n \times W

                = 0.594 \times 16.04

                = 9.54 lb

Hence, molecular weight of the gas is 9.54 lb.

  • We will calculate the density as follows.

                d = \frac{PM}{RT}

                    = \frac{1500 \times 16.04}{10.73 \times 564}

                    = 3.975 lb/ft^{3}

  • Now, calculate the specific gravity of the gas as follows.

  Specific gravity relative to air = \frac{\text{density of methane}}{\text{density of air}}

                         = \frac{3.975 lb/ft^{3}}{0.0765 lb/ft^{3}}

                         = 51.96

6 0
3 years ago
A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed
Archy [21]

Answer:

The molar mass of the acid is 167.5 g/mol

Explanation:

A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed a single end point after 19.31 mL of 0.1243 M NaOH had been introduced. Calculate the molecular mass of the acid.

Step 1: Data given

Mass of the sample of a purified organic acid = 0.4021 grams

Molarity = 0.1243 M

Volume needed to reach the end point = 19.1 mL = 0.01931 L

Step 2: Calculate the number of moles NaOH

Moles NaOH = molarity NaOH  * volume

Moles NaOH = 0.1243 M * 0.01931 L

Moles NaOH = 0.00240 moles

Step 3: Calculate moles of the acid

We'll need 0.00240 moles of acid to neutralize 0.00240 moles of NaOH ( it's a single end point)

Moles acid = 0.00240 moles

Step 4: Calculate molar mass of the acid

Molar mass = mass / moles

Molar mass = 0.4021 grams / 0.00240 moles

Molar mass = 167.5 g/mol

The molar mass of the acid is 167.5 g/mol

6 0
3 years ago
Explain what would happen to the air temperature at Riverdale School over the course of the
Ira Lisetskai [31]

Answer:

In each Amplify Science unit, students figure out

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the phenomenon works. The Coherence Flowchart

visually represents the storyline of the unit, showing

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support students as they build complex explanations

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Flowchart on the following pages (one chapter per

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Explanation:

7 0
2 years ago
How does changing the volume or temperature of a gas affect the pressure of that gas?
Masja [62]

Answer:

When a gas occupies a smaller volume, it exerts a higher pressure; when it occupies a larger volume, it exerts a lower pressure (assuming the amount of gas and the temperature do not change). Since P and V are inversely proportional, a graph of 1/P vs. V is linear.

Explanation:

<h2><u><em>This is all I know.</em></u></h2><h2><u><em>Hope it helps~</em></u></h2><h2><u><em>Good luck with your work!!~</em></u></h2>
6 0
2 years ago
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