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melamori03 [73]
3 years ago
7

Quickfire questions

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
6 0
Nzhzhbzsbbzbsbbzbzbzbz
AysviL [449]3 years ago
4 0

Answer:

10 4 for question one

Step-by-step explanation:

I don't have one I just know how and I did this

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It rained 5/8 each day for 5 days how much total rain fell
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15 hours

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Solve the equation!!!<br> 3y=2(2+2y)
antiseptic1488 [7]

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3y= 2(2+2y)

Distribute it out : 3y=4+2y

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What is the y-intercept of the line perpendicular to the line y = 4/3x + 1 that includes the point (4, 1)?
Alexeev081 [22]

\bf y=\stackrel{\downarrow }{\cfrac{4}{3}}x+1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{4}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{4}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{4}}}

so then, we know this line has a slope of -3/4 and runs through (4 , 1)

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{1})~\hspace{10em} slope = m\implies -\cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-1=-\cfrac{3}{4}(x-4)\implies y-1=-\cfrac{3}{4}x+3

\bf y=-\cfrac{3}{4}x\stackrel{\downarrow }{+4}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hfill \stackrel{\textit{y-intercept}}{(0,4)}

3 0
3 years ago
Help me pls !!!!!!!!!!
Irina18 [472]

Answer: What do u need help with?

Step-by-step explanation:

6 0
2 years ago
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