Bruh what THERES nothing to help no pic or anything luv
Answer:
B
Step-by-step explanation:
![6^{\frac{1}{4} } b^{\frac{3}{4} }c^{\frac{1}{4} }\\\\=(6^1b^3c^1)^{\frac{1}{4} }\\\\=(6b^3c)^\frac{1}{4} \\\\=\sqrt[4]{6b^3c}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20b%5E%7B%5Cfrac%7B3%7D%7B4%7D%20%7Dc%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%5C%5C%5C%5C%3D%286%5E1b%5E3c%5E1%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%5C%5C%5C%5C%3D%286b%5E3c%29%5E%5Cfrac%7B1%7D%7B4%7D%20%5C%5C%5C%5C%3D%5Csqrt%5B4%5D%7B6b%5E3c%7D)
so answer is B
The answer to the problem is A
Answer:
As given, measure of angle 4 is 70°
Then what would be the measure of ∠8.
Following cases comes into consideration
1. If ∠4 and ∠8 are supplementary angles i.e lie on same side of Transversal, then
∠4 + ∠8=180°
⇒70°+∠8=180° [∠4=70°]
⇒∠8=180°-70°
⇒∠8=110°
<u>2nd possibility</u>
But if these two angles i.e ∠4 and ∠8 forms a linear pair.Then
⇒ ∠4 + ∠8=180°
⇒70°+∠8=180° [∠4=70°]
⇒∠8=180°-70°
⇒∠8=110°
<u>3rd possibility</u>
If ∠4 and ∠8 are alternate exterior angles.
then, ∠4 = ∠8=70°
<u>4th possibility</u>
If If ∠4 and ∠8 are corresponding angles.
then, ∠4 = ∠8=70°
Out of four options given Option A[ 110° because ∠4 and ∠8 are supplementary angles], Option B[70° because ∠4 and ∠8 are alternate exterior angles.] and Option D[70° because ∠4 and ∠8 are corresponding angles.] are Correct.