Let’s put it from least to greatest.
3 8 6 9 10 12 13
The median is 9.
Quartile one is 8
Quartile 3 is 12
12-8
4 is the IQR
2x - 2y = 12
-2x - 3y = -22
solution could be (x,2)
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2x - 6y = 10
x + 8y = 5
solution could be : (5,y)
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3x - y = -5
x + 4y = 7
solution could be : (x,2)
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x + y = 2
2x + y = 13
solution could be : neither....is this one written correctly ?
If the car is traveling at 36ft/s per converted mph divide the amount of travel length the person will travel and subtract is by 1 this being the second tracked which is 36ft/s
Answer:
join
Step-by-step explanation:
meet./vyc-hwbw-svg
Answer:
Step-by-step explanation:
<u>For old circular garden:</u>
take the radius as r.
then use the formula to find area of circle: πr² ......this is old garden area.
<u>For new enlarged garden:</u>
the radius is twice the old radius so, radius = 2 * r = 2r ......enlarged radius
now find area for this new garden: π(2r)² → 4πr²
In common fractions: (old garden)/(new garden)
: ( πr² ) / ( 4πr² )
: 1/4