Question

An airplane flies due north at 100 m/s through a 30 m/s cross wind blowing from the east to the west. Determine the resultant velocity of the airplane.

Answer 1

Answer:

The resultant velocity of the airplane is 104.4 m/s.

Explanation:

It is given that,

Velocity of airplane, $v_1=100\ m/s$ (due north)

Velocity of wind, $v_2=30\ m/s$ (east to the west)

We need to find the resultant velocity of the airplane. The resultant velocity is given by :

$v=\sqrt{v_1^2+v_2^2}$

$v=\sqrt{(100)^2+(30)^2}$

v = 104.4 m/s

So, the resultant velocity of the airplane is 104.4 m/s. Hence, this is the required solution.

Answer 2

Vf=√30²+100²
Vf=104 m/s

|Ф|=tan inverse of |100÷30|
Ф= 73 degrees

Therefore the resulting velocity of the airplaine is 104 m/s [ 73 degrees N of W]