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larisa [96]
4 years ago
12

A basic observation of a star is how bright it appears. This brightness is known as the star's

Chemistry
2 answers:
AfilCa [17]4 years ago
8 0
The brightness is often known as the star's apparent magnitude when they do a basic observation of how bright the star appears.
Elan Coil [88]4 years ago
4 0

Answer is: B. apparent magnitude.

The magnitude of star is a measure of its brightness. The lower the magnitude number, the brighter the star.

Apparent magnitude is the brightness of a star as seen from Earth.

Absolute magnitude is the apparent magnitude of a star (or some other astronomical object) if it were 32.6 light years away from Earth and in the absence of any sources (dust, gases) that could interfere with its brightness.

Luminosity is the total amount of energy emitted per unit of time by a star.

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It requires two sticks of butter to make a batch of 20 cookies. How much butter will it take to make 150 cookies?
liq [111]

Answer:

It would take 15 sticks of butter

Explanation:

2 divided by 20 is 0.1

0.1 is how much butter for 1 so now we multiply that by 150

0.1 x 150 = 15

Therefore, you would need 15 sticks of butter for 150 cookies

6 0
3 years ago
Calculate the fraction of lattice sites that are Schottky defects for cesium chloride at 623 oC (this temperature is below the m
Degger [83]

Answer:

5.9 × 10^-6.

Explanation:

In the arrangements of crystal solids there is likely going to be an imperfection or defect and one of the defect or imperfections in the arrangements of solids is known as the Schottky defects. The Schottky defects is a kind of lattice arrangements imperfection that occurs when positively charged ions and negatively charged ions leave their position.

So, let us delve right into the solution of the question. We will be making use of the formula below;

Wb/ W = e^ - c/ 2kT.

Where Wb/ W= fraction of lattice sites, c= energy for defect formation = 1.86 eV, and T = temperature= 623° C= 896 k.

So, Wb/ W = e ^ -1.86/ (2 × 896 × 8.62 × 10^ -5).

Wb/ W= 0.000005896557435956372.

Wb/ W=5.9 × 10^-6.

3 0
3 years ago
Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9
EleoNora [17]

Answer : The current passing between the electrodes is, 1.056\times 10^{-2}A

Explanation :

First we have to calculate the charge of sodium ion.

q=ne

where,

q = charge of sodium ion

n = number of sodium ion = 2.68\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C

Now we have to calculate the charge of chlorine ion.

q'=ne

where,

q' = charge of chlorine ion

n = number of chlorine ion = 3.92\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C

Now we have to calculate the current passing between the electrodes.

I=\frac{q}{t}+\frac{q'}{t}

I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}

I=1.056\times 10^{-2}A

Thus, the current passing between the electrodes is, 1.056\times 10^{-2}A

4 0
3 years ago
Why are intensive properties useful for identifying a substance?
Lesechka [4]

Answer:

d

They do not depend on the amount of substance you have.

3 0
3 years ago
I REALLY NEED THE HELP
timama [110]

Answer:4

Explanation:number 4 is the right answer :)

7 0
2 years ago
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