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SSSSS [86.1K]
3 years ago
10

Fill in the blanks with its definition or description.

Chemistry
1 answer:
amm18123 years ago
8 0

Answer:

a) equivalence point

b) direct titration

c) primary standard

d) titrand

e) Back titration

f) back titration

g) standard solution

h) standard solution

I) indirect titration

j) end point

Explanation:

A volumetric analysis is one in which a solution of unknown concentration is determined from its volume. This is commonly referred to as titration.

In titration, a standard solution is reacted with another solution of unknown concentration. The point at which the concentration of the standard solution is equal to that of the analyte is known as the equivalence point (usually indicated by a colour change). An indicator may be added to the analyte solution to help identify when the reaction is complete.

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The empirical formula for two compounds that have very different properties (one tastes very sour and the other very sweet) is c
DiKsa [7]

I believe that the choices for this question are:

C2H4O2, C4H8O4 <span>
CH2O, C6H12O6 
C3H6O3, C6H12O6 
C2H4O2, C6H12O6 </span>

 

The answer to this based on the molar masses given is:

C2H4O2, C6H12O6 

 

To prove calculate the molar mass:

C2H4O2 = 2*12 + 4*1 + 2*16 = 60

C6H12O6 = 6*12 + 12*1 + 6*16 = 180

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3 years ago
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What is the molecular formula for Heptachlorine hexoxide?
natka813 [3]

Answer:

D. CI706

Explanation:

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3 years ago
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How often does the water cycle occur on earth?
elena55 [62]

Answer:

A

Explanation:

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7 0
3 years ago
What is the result of multiplying 2.5 × 10^10 by 3.5 × 10-^2
LUCKY_DIMON [66]
2,5*10^{10}*3,5*10^{-2}=8,75*10^{10+(-2)}=8,75*10^{8}
7 0
4 years ago
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The flavor of anise is due to anethole, a compound with the molecular forumal C10H12O. Combustion of one mole of anethole produc
AfilCa [17]

Answer:

Change in temperature of calorimeter is 4.52^{0}\textrm{C}

Explanation:

Molar mass of anethole = 148.2 g/mol

So, 0.950 g of anethole = \frac{0.950}{148.2}moles of anethole = 0.00641 moles of anethole

1 mol of anethole releases 5541 kJ of heat upon combustion

So, 0.00641 moles of anethole release (5541\times 0.00641)kJ of heat or 35.52 kJ of heat

7.854 kJ of heat increases 1^{0}\textrm{C} temperature of calorimeter.

So, 35.52 kJ of heat increases (\frac{1}{7.854}\times 35.52)^{0}\textrm{C} or 4.52^{0}\textrm{C} temperature of calorimeter

So, change in temperature of calorimeter is 4.52^{0}\textrm{C}

7 0
3 years ago
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