Answer: There are 0.5 grams of barium sulfate are present in 250 of 2.0 M 
solution.
Explanation:
Given: Molarity of solution = 2.0 M
Volume of solution = 250 mL
Convert mL int L as follows.
Molarity is the number of moles of solute present in liter of solution. Hence, molarity of the given solution is as follows.
Thus, we can conclude that there are 0.5 grams of barium sulfate are present in 250 of 2.0 M solution.
Answer:
Atomic number 26,atomic mass 26+30=56 dalton and net charge is 3+
Explanation:
The total number of proton present in an atom is known as the atomic number of that atom.From that point of view the atomic number of iron ion is 26.
The total number proton and neutrons present in the nucleus of an atom or ion is termed as atomic mass.From that point of view the the atomic mass of iron ion is 26+30=56 dalton
According to the given question iron ion contain 3 more protons than electrons as a result the iron ion will contain 3 unit positive charge.
Answer:
c.- How much of the reactants are needed and how much product will made.
Explanation:
The moles is the matter unit used in chemistry to simplify some calculations, instead of using grams. Also the moles are very useful because the chemical reaction can be balanced.
When a Chemical reaction is balanced, then it can be easily to calculate how many moles are necessary to add in a process to obtain a quantity of grams of a product.
Answer:
Here's what I find
Explanation:
Heisenberg observed that if we want to locate a moving electron, we must bounce photons off it.
However, this makes it recoil. By the time the photon returns to our eye, the electron will no longer be in the same place.
He concluded that there is a limit to the precision with which we can simultaneously measure the position and speed (momentum) of a particle.
The more precisely we know the electron's speed, the less precisely we know its position and vice versa.
The uncertainty in the product of the two values cannot be less than a fixed small number.
It dissolves I think I know I am expert and. Ute
