Answer:

Step-by-step explanation:
*Move terms to the left and set equal to zero:
4㏒(√x) - ㏒(3x) - ㏒(x²) = 0
*simplify each term:
㏒(x²) - ㏒(3x) - ㏒(x²)
㏒(x²÷x²) -㏒(3x)
㏒(x²÷x² / 3x)
*cancel common factor x²:
㏒(
)
*rewrite to solve for x :
10⁰ = 
1 = 
1 · x =
· x
1x = 
*that would be our answer, however, the convention is to exclude the "1" in front of variables so we are left with:
x = 
Let's see
![\sf [0.5\:0.5]\left[\begin{array}{cc}\sf b_1 &\sf r_1\\ \sf b_2&\sf r_2\end{array}\right]](https://tex.z-dn.net/?f=%5Csf%20%5B0.5%5C%3A0.5%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Csf%20b_1%20%26%5Csf%20r_1%5C%5C%20%5Csf%20b_2%26%5Csf%20r_2%5Cend%7Barray%7D%5Cright%5D)
r_1 and r2 are costs per pound
So
- It's r_1 is the cost of 1/2 pound rice at market one and r_2 is at market 2
Option J