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Svetach [21]
2 years ago
14

What is the sum of 3 consecutive odd numbers is 69 what is the third number in the sequence

Mathematics
1 answer:
Blizzard [7]2 years ago
7 0
The answer to the question is 23.
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I need answers please.
Lena [83]

Answer:

1) 477.5

2) 395.8

3) 2042.0

4)132.7

5) 44.1

6) 437.9

Step-by-step explanation:

Surface area of a cylinder = 2(pi)(r)(h) + 2 (pi)(r)^2

Lateral area of a cylinder = 2 (pi)(r)(r)

7 0
3 years ago
Could someone please help me with this answer
MArishka [77]

Answer: H

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
6.) Which trigonometric function is equal to Cos 84°?
lidiya [134]
It's sin 6 .....so b is the answer !
5 0
2 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
I’ll give Brainliest!!
Gnoma [55]
Answer: 1.5

Step-by-step explanation: The difference between the 2nd And 4th is 7. Divide by 2 to get 3.5. Add 3.5 to f(2) to getf(3)
The difference between f(1) and f(2) will be 3.5 and that's 5-3.5 =1.5
F(5) is 15.5 f(6) is 19

7 0
2 years ago
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