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Aleksandr-060686 [28]
3 years ago
13

The following information pertains to the January operating budget for Casey Corporation. ∙ Budgeted sales for January $200,000

and February $107,000. ∙ Collections for sales are 40% in the month of sale and 60% the next month. ∙ Gross margin is 25% of sales. ∙ Administrative costs are $11,000 each month. ∙ Beginning accounts receivable is $26,000. ∙ Beginning inventory is $15,000. ∙ Beginning accounts payable is $68,000. (All from inventory purchases.) ∙ Purchases are paid in full the following month. ∙ Desired ending inventory is 25% of next month's cost of goods sold (COGS).
Engineering
1 answer:
stich3 [128]3 years ago
5 0

Answer:

For January, budgeted cost of goods sold is $150,000

Explanation:

Sales is the consists of Gross income and Cost of goods sold. We can derive the gross income value after deducting cost of goods sold from sales value.

Budgeted Sales for next month = $200,000

Gross Margin = 25%

Gross Margin = Gross Income / Sales

25% = Gross Income / $200,000

Gross Income is the net value of sales and cost of goods sold.

Gross Income = $200,000 x 25%

Gross Income = $50,000

As we know,

Gross Income = Sales - Cost of Goods sold

$50,000 = $200,000 - Cost of Goods sold

Cost of Goods sold = $200,000 - $50,000

Cost of Goods sold = $150,000

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Answer:

Explanation: see attachment below

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3 years ago
/ Air enters a 20-cm-diameter 12-m-long underwater duct at 50°C and 1 atm at a
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Answer:

A) EXIT TEMPERATURE = 14⁰C

b) rate of heat transfer of air = - 13475.78 = - 13.5 kw

Explanation:

Given data :

diameter of duct = 20-cm = 0.2 m

length of duct = 12-m

temperature of air at inlet= 50⁰c

pressure = 1 atm

mean velocity = 7 m/s

average heat transfer coefficient = 85 w/m^2⁰c

water temperature = 5⁰c

surface temperature ( Ts) = 5⁰c

properties of air at 50⁰c and at 1 atm

= 1.092 kg/m^3

Cp = 1007 j/kg⁰c

k = 0.02735 W/m⁰c

Pr = 0.7228

v  = 1.798 * 10^-5 m^2/s

determine the exit temperature of air and the rate of heat transfer

attached below is the detailed solution

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= p*Ac*Vmean

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4 0
3 years ago
At a given point in a supersonic wind tunnel, the pressure and temperature are 5×104 N/m2 and 200 K, respectively. The total pre
Ne4ueva [31]

Answer:

The Mach number is 2.866

Total temperature To = 528.524K

Explanation:

Pressure (P)= 5 * 10^4 N/m^2

Total pressure (Po) =  1.5 * 10^6 N/m^2

Temperature (T) = 200K

For air, r= 1.4

To find the Mach number we use:

Po/P = [1 + (r - 1/2) M^2] ^ r^/^r^-^1

1.5 * 10^6 / 5 * 10^4 =[ 1 + (1.4 -1 /2) (M^2) ] ^ 1^.^4^/^1^.^4^-^1

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(0.3 * 10^2)^(1/3.5) = 1 + 0.2M^2

2.6426 = 1 +0.2M^2

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M = sqrt(1.6426/0.2)

M = 2.866

To find Total Temperature :

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4 0
3 years ago
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aniked [119]

<u>Answer:</u>

The plasma membrane encloses specific structures.

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