Answer:
Hello there, the question is not complete, but not to worry you can check the explanation section to check how you can solve a similar question or to be be able to solve the exact question directly.
Explanation:
The flow of electrons is what is known or refer to as Current. When energy is used on a nuclei, the electrons are forced to move from one position to the other. The direction of flow of electron is from the negative terminal which then moves to the positive terminal.
Therefore, it can be said that the positive charge determines the direction of electron flow. The starting point is the negative terminal, in which it will now move in the direction in which the positive terminal is.
Answer:
(C) Prototype Model
Explanation:
I'm sure that is the answer i am very sorry if not :)
Answer:
a) 144.000 s
b) and c)Battery voltage and power plots in attached image.
where D:{0<t<40} h
d) 1620 J
Explanation:
a) The first answer is a rule of three

b) Using the line equation with initial point (0 seconds, 1.5 V)
where m is the slope.

where V is voltage in V, and t is time in seconds
and using P and m.
![V=-\frac{0.5}{144000} t + 1.5 V[tex] c) Using the equation VPOWER IS DEFINED AS:[tex] P(t) = v(t) * i(t) [tex]so.[tex] P(t) = 9mA * (-\frac{0.5}{144000} t + 1.5) [tex][tex]P(t) = - (31.25X10^{-9}) t + 0.0135](https://tex.z-dn.net/?f=V%3D-%5Cfrac%7B0.5%7D%7B144000%7D%20t%20%2B%201.5%20V%5Btex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%20%3C%2Fp%3E%3Cp%3E%3Cstrong%3Ec%29%20Using%20the%20equation%20V%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EPOWER%20IS%20DEFINED%20AS%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%20P%28t%29%20%3D%20v%28t%29%20%2A%20i%28t%29%20%5Btex%5D%3C%2Fp%3E%3Cp%3Eso.%3C%2Fp%3E%3Cp%3E%5Btex%5D%20P%28t%29%20%3D%209mA%20%2A%20%28-%5Cfrac%7B0.5%7D%7B144000%7D%20t%20%2B%201.5%29%20%5Btex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3E%5Btex%5DP%28t%29%20%3D%20-%20%2831.25X10%5E%7B-9%7D%29%20t%20%2B%200.0135)
d) Having a count that.


Answer:
First we determine the tensile strength using the equation;
Tₓ (MPa) = 3.45 × HB
{ Tₓ is tensile strength, HB is Brinell hardness = 225 }
therefore
Tₓ = 3.45 × 225
Tₓ = 775 Mpa
From Conclusions, It is stated that in order to achieve a tensile strength of 775 MPa for a steel, the percentage of the cold work should be 10
When the percentage of cold work for steel is up to 10,the ductility is 16% EL.
And 16% EL is greater than 12% EL
Therefore, it is possible to cold work steel to a given minimum Brinell hardness of 225 and at the same time a ductility of at least 12% EL
Answer:
Explanation:
Given that:
From process 1 → 2



Process 2 → 3
The volume is constant i.e 

Process 3 → 1
P = constant i.e the compression from state 1
Now, to start with 1 → 2




The work-done for the process 1 → 2 through adiabatic expansion is:
![W = \dfrac{1}{1-\gamma}[P_2V_2-P_1V_1]](https://tex.z-dn.net/?f=W%20%3D%20%5Cdfrac%7B1%7D%7B1-%5Cgamma%7D%5BP_2V_2-P_1V_1%5D)
We know that 1 bar = 
∴
![W = \dfrac{1}{1-1.5}[1.25 \times 10^5 \times 4- 10 \times 10^5 \times 1]](https://tex.z-dn.net/?f=W%20%3D%20%5Cdfrac%7B1%7D%7B1-1.5%7D%5B1.25%20%5Ctimes%2010%5E5%20%5Ctimes%204-%2010%20%5Ctimes%2010%5E5%20%5Ctimes%201%5D)


For process 2 → 3
Since V is constant
Thus:
W = PΔV = 0

For process 3 → 1
W = PΔV





The net work-done now for the entire system is :



The sketch of the processes on p -V coordinates can be found in the image attached below.