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snow_lady [41]
2 years ago
9

What is the best way to organize desert several several million different types of organisms on earth

Chemistry
1 answer:
SCORPION-xisa [38]2 years ago
5 0

Answer:

The desert should be divided into different types based on its properties. The organisms living in specific type of desert should be named accordingly.

Explanation:

There are usually five major types of desert in the world. Tropical, rainy, semi arid desert, coastal desert and dry desert. There are many different types of organisms living in these deserts. The biodiversity has made it difficult for the humans to analyse and identify the millions of different types. The best way is to organize and name the organisms that live in specific types of deserts.

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What factor impacts the possible number of ways in which different atoms can be put together
Llana [10]
There is 3 ways that an atom can be put together
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3 years ago
The charges of a set of isoelectronic ions vary from 3+ to 3-. Place the ions in order of increasing size.
ser-zykov [4K]

Answer:

Explanation:

  Iso-electronic species have same number of electrons . Positive charged ions will have smaller size . As electrons add , size increases due to electronic repulsion .

Following species are isoelectronic .

Al³⁺ < Mg²⁺ < Na¹⁺ < Ne < F⁻¹ < O⁻² < N⁻³

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What does saturated mean in science?<br>​
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5 0
2 years ago
Read 2 more answers
Write a balanced redox equation for the reaction that occurs cr dissolves in 1 m h2cr2o7.
galben [10]
When Cr dissolves in 1 M H₂Cr₂O₇
Cr(s) ⇄ Cr³⁺ + 3 e⁻
Cr₂O₇²⁻ + 14 H⁺ + 6 e⁻ ⇄ 2 Cr³⁺ + 7 H₂O
by multiplying the first equation by 2 and add the 2 equations;
The balanced redox reaction will be:
2 Cr(s) + Cr₂O₇²⁻(aq) + 14 H⁺(aq) → 4 Cr³⁺(aq) + 7 H₂O(l)

3 0
3 years ago
If an automobile air bag has a volume of 11.7 L, what mass of NaN3 (in g) is required to fully inflate the air bag upon impact
Usimov [2.4K]

Answer:

33.95 grams of NaN3

Explanation:

Number of moles of NaN3 = mass (m)/MW = m/65 mole

I mole of NaN3 requires 22.4L air bag

m/65 mole of NaN3 required 11.7L

22.4m/65 = 11.7

22.4m = 65×11.7

22.4m = 760.5

m = 760.5/22.4 = 33.95grams of NaN3

5 0
2 years ago
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