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liberstina [14]
3 years ago
8

I do not enjoy chem at all someone plz help me

Chemistry
1 answer:
Pie3 years ago
4 0

Option A: Electrons flow from nickel fork to silver rod, which is a cathode.

In a cell, an electrode with lower standard reduction potential will undergo oxidation and act as an anode and the one with higher standard reduction potential will undergo reduction and act as a cathode. The movement of electrons always takes place from anode to cathode.

In the given cell, silver rod and nickel fork are taken as metal electrodes. The reduction half reaction of silver and nickel are as follows:

Ag^{+}(aq)+e^{-}\rightarrow Ag(s)

Ni^{2+}  (aq)+2e^{-}\rightarrow Ni(s)

Here, the standardE^{0}(V) electrode reduction potential of silver and nickel is 0.80 V and -0.26 V. Since, the electrode potential of silver is more than that of nickel thus, silver rod will undergo reduction and it will be cathode.  Nickel fork will be anode as it undergoes oxidation.

Since, electrons flow from anode to cathode thus, it flows from Ni electrode to Ag electrode.

It satisfies the statement A, electrons flow from nickel fork to silver rod, which is a cathode. Therefore, correct option is A.


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What is SI unit of e.m.f and p.d.​
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Answer:

Electromotive force or e.m.f is defined as the battery's energy per Coulomb of charge passing through it. like other measures of energy per charge emf has SI unit of volts , equivalent to joules per coulomb.

8 0
3 years ago
Find the empirical formula of the following compounds:
Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus \frac{mol phosphorus}{ 30.97 g phosphorus}= 0.0293 mol

Moles bromine 6.99 g bromine\frac{mol bromine}{79.90 g bromine}=0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

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8 0
1 year ago
What kind of bond is formed when electrons are gained or lost ?
lisov135 [29]
C.) Ionic bond is formed between that...
3 0
4 years ago
(a)kcl ionic (b)p4 nonpolar covalent (c)bf3 nonpolar covalent (d)so2 nonpolar covalent (e)br2 nonpolar covalent (f)no2 nonpolar
Angelina_Jolie [31]

Because K and Cl have such a large disparity in their electronegativities, KCl is a bipolar ionic molecule.

<h3>What exactly are polar and nonpolar bonds?</h3>

Polar covalent bonds develop when the distribution of electrons among atoms is uneven, whereas nonpolar side chains develop when the distribution of electrons is more even. The reason for the unequal sharing of electrons is because the atoms receiving them have various electronegativities.

<h3>How are polar bonds created?</h3>

Whenever a single pair of electrons is not shared equally, a polar molecule bond is created. This is caused by the electronegativity difference between the two elements. An unit of h as well as an unit of bromine share a pair of electrons, but not evenly.

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8 0
1 year ago
What ion (cation or anion and charge) do the halogen group (17) form to fulfill the octet
Dafna11 [192]

Answer:

option B= anion (-1)

Explanation:

The halogens are present in the P- block of periodic table. There are thirty five elements present in p-block. The halogens are present in group seventeen. Their are seven electrons are present in valance sheet. All halogens require one electron to complete the octet and form anion carry -1 charge.

Halogens include following elements:

Fluorine, chlorine, bromine, iodine and astatine.

The halogens mostly form single bond with the other elements by gaining one electron and -1 charge. These are most reactive non-metals.

Properties of some halogen elements:

Fluorine:

1. It is yellow in color.

2. It is flammable gas.

3. It is highly corrosive.

4. Fluorine has pungent smell.

5. It's reactions with all other elements are vigorous except neon, oxygen, krypton and helium.  

Chlorine:

1. It is greenish-yellow irritating gas.

2. Its melting point is 172.2 K.

3. Its boiling point is 238.6 K.

4. It is disinfectant and can kill the bacteria.

5. It is also used in manufacturing of paper, paints and textile industries.

Iodine:

1. It is present in solid form.

2. It is crystalline in nature.

3. It is very corrosive and has pungent odor.

4. It can not react with oxygen and nitrogen.

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