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vekshin1
3 years ago
6

Mg(NO3)2 soluble or insoluble?

Chemistry
1 answer:
hammer [34]3 years ago
7 0

Answer:

The chemical compound Mg(NO3)2, also known as magnesium nitrate, is very soluble, especially in water.

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Although Rutherford is credited with the famous gold foil scattering experiment, he didn’t actually conduct this experiment hims
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3 years ago
The mass percent of carbon in a typical human is 18%, and the mass percent of 14C in natural carbon is 1.6 × 10-10%. Assuming a
Tema [17]

Answer:

4066 decay/s

Explanation:

Given that:-

The weight of the person is:- 190 lb

Also, 1 lb = 453.592 g

So, weight of the person = 86182.6 g

Also, given that carbon is 18% in the human body. So,

\%\ Carbon=\frac{18}{100}\times 86182.6\ g=15512.868\ g

Carbon-14 is 1.6\times 10^{-10}\ \% of the carbon in the body. So,

\%\ Carbon-14=\frac{1.6\times 10^{-10}}{100}\times 15512.868\ g=2.48\times 10^{-8}\ g

Also,

14 g of Carbon-14 contains  6.023\times 10^{23} atoms of carbon-14

So,  

2.48\times 10^{-8}\ g of Carbon-14 contains  \frac{6.023\times 10^{23}}{14}\times 2.48\times 10^{-8} atoms of carbon-14

Atoms of carbon-14 =  1.07\times 10^{15}

Given that:

Half life = 5730 years

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac{ln\ 2}{5730}\ years^{-1}

The rate constant, k = 0.00012 years⁻¹

Also, 1 year = 3.154\times 10^7 s

So, The rate constant, k = \frac{0.00012}{3.154\times 10^7} s⁻¹ = 3.8\times 10^{-12}\ s^{-1}

Thus, decay events per second = K\times atoms decayed = 3.8\times 10^{-12}\times 1.07\times 10^{15}\ decay/s = 4066 decay/s

4 0
3 years ago
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