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3 years ago

Explain how the removal of thermal energy (heat) from matter affects its particles

Chemistry

1 answer:

den301095 [7]3 years ago

6 0

Answer:

You can change an object's state of matter by adding or removing thermal energy. When you add thermal energy to an object, these things can happen: Particles move faster

Explanation:

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If the half life of a radioactive isotope is 1 day, then how much of the original isotope remains at the end of two days?

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25%

Explanation:

In a half life of a radioactive isotope is 1 day,it means it loses its half mass each day

We a formula for N half life

$\sf { \frac{1}{2} }^{n}$

where n is the number of days

Here the isotope is kept for 2 days

so it's left over mass will be

$\sf { (\frac{1}{2}) }^{2} \\ \\ \\ \frac{1}{2} \times \frac{1}{2} \\ \\ \sf \frac{1}{4}$

It's left over mass 1/4th of the original mass

Now, we need to find it's percentage by multiplying with 100

$\sf \frac{1}{4} \times 100 \%\\ \\ \sf \cancel\frac{100}{4} \% \\ \\ \sf 25\%$

So 25% mass will be left after 2 day of half life radioactive isotope.

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3 years ago

As the number of electrons added to the same principal energy level increases, atomic size generally

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If a graduated cylinder has 28ml of water in it and you add an object which causes the water level to rise to 47ml, what is the

grin007 [14]

Answer:

The object placed in the water has a volume of 19 cm³

Explanation:

Step 1: Data given

volume of the cylinder before adding the object = 28 mL = 28 cm³

After adding an object with volume X the volume rises to 47 mL = 47 cm³

Step 2: Calculate the volume of the object

Volume of the object = Final volume - initial volume

Volume of the object = 47 cm³ (or 47 mL) - 28 cm³ ( or 28 mL) = 19 cm³ (or 19 mL)

The object placed in the water has a volume of 19 cm³

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3 years ago