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NISA [10]
3 years ago
7

Four different solutions (I, II, III, and IV) are labeled on the pH scale below. A p H scale is shown, fading from red at the le

ft end to blue at the right. p H is shown in even increments from 0 to 14. Points marked are: Roman numeral 1 at 1 on the scale, Roman 2 at 6, Roman 3 at 11, and roman 4 at 13. Why would solution IV be considered the most concentrated base out of the four substances? It has the highest concentration of hydrogen ions. It has the highest concentration of hydronium ions. It has the highest concentration of oxide ions. It has the highest concentration of hydroxide ions.
Chemistry
2 answers:
andreyandreev [35.5K]3 years ago
6 0

Answer: It has the highest number of hydroxide ions

Explanation: I took the review

LekaFEV [45]3 years ago
3 0

Answer:

It has the highest concentration of hydroxide ions.

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10-10 above the 0 is positive and the ones below is - (negitive)

Explanation:

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Waves of sound energy move ________ ___ ____ ___________ from the source.
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2 years ago
We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to
andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

  • To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of the NaOH.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of the Ca(OH)_2

We are given:

n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL  

Putting all the values in above equation, we get:

M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M

  • To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base.

We are given:

n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL

Putting values in above equation, we get:

1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M

Hence, the correct answer is Option 5.

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It has 78 neutrons in a cesium
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